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VARVARA [1.3K]
1 year ago
14

Formic acid, which is a component of insect venom, has a ka = 1. 8 ✕ 10-4. what is the [h3o ] in a solution that is initially 0.

10 m formic acid, hcooh?
Chemistry
1 answer:
Mashutka [201]1 year ago
5 0

The [H3O+ ] in a solution that is initially 0. 10 m formic acid, hcooh is 0.00415M.

<h3>What is formic acid? </h3>

Formic acid is defined as the simplest carboxalic acid which contain one carbon atom. It is weak acid.

  • Another name of formic acid is methanoic acid.
  • It is used as the preservation and antibacterial agent in livestock feed.
  • Exposure to Formic Acid can cause headache, dizziness, nausea and vomiting. individuals, may cause a skin allergy.

Thus we concluded from the image that the

concentration of [H30+] is 0.00413M.

learn more about formic acid:

brainly.com/question/25030986

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What is the correct name for: C3S5?
scZoUnD [109]

Answer:

Trithioxodithiole

Explanation:

5 0
3 years ago
How many kilograms of solvent would contain 0.43 mol of CaO in a 2.5 molality solution
dalvyx [7]
<h3>Answer:</h3>

0.024 kg CaO

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Aqueous Solutions</u>

  • Molarity = moles of solute / liters of solution

<u>Atomic Structure</u>

  • Reading a Periodic Tables
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.41 mol CaO

2.5 M Solution

<u>Step 2: Identify Conversions</u>

1000 g = 1 kg

Molar Mass of Ca - 40.08 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CaO - 40.08 + 16.00 = 56.08 g/mol

<u>Step 3: Convert</u>

  1. Set up:                                \displaystyle 0.43 \ mol \ CaO(\frac{56.08 \ g \ Cao}{1 \ mol \ CaO})(\frac{1 \ kg \ CaO}{1000 \ g \ CaO})
  2. Multiply:                              \displaystyle 0.024114 \ kg \ CaO

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our lowest.</em>

0.024114 kg CaO ≈ 0.024 kg CaO

4 0
3 years ago
Read 2 more answers
How many milliliters of 0. 0140 m na2s2o3 solution are needed to dissolve 0. 590 g of agbr? agbr(s) 2na2s2o3(aq)→na3ag(s2o3)2(aq
Marina86 [1]

The molarity of the solution can be used to give the moles and the volume of the solution. The 0.0140 M sodium thiosulfate needs 225 ml of volume.

<h3>What is molarity?</h3>

Molarity is the property of the solution that is given by the ratio of the moles of the solute to the volume of the solution in liters.

Given,

Molarity of Sodium thiosulfate = 0.0140 M

Mass of solute (AgBr) = 0.590 gm

Molar mass of AgBr = 187.77 g/mol

First moles from the mass can be calculated as,

Moles = mass ÷ molar mass

n = 0.590 g ÷ 187.77 g/mol

= 0.00314 moles

Now, the volume of the solution from molarity is calculated as,

Volume = moles ÷ molarity

= 0.00314 moles ÷ 0.0140

= 0.225 L

Therefore, 225 mL is the volume required.

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3 0
2 years ago
Pick 1 answer, please help!
olga nikolaevna [1]

Answer:

B

Explanation:

6 0
3 years ago
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Select the correct answer.
Dmitry [639]

Answer:

A number is right I think

8 0
3 years ago
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