The two solutions that have similar solubilities at 40°C will be Na₂HAsO₄ and Na₂SO₄.
<h3>
What is solubity ?</h3>
It is the ability of a solute to be dissolved, especially in water.
As the temperature increases the solubility of the gas generally decreases"
According to given information and graph attached as reference ;
- Solubility of NaCl (sodium chloride) at 40°C is 36.3 grams.
- Solubility of Na₂SO₄ (sodium sulfate) at 40°C is 48.8 grams.
- Solubility of Na₂HAsO₄ (sodium arsenate dibasic) at 40°C is 48.9
grams. - Solubility of Ba(NO₃)₂ (barium nitrate) at 40°C is 14.1 grams.
- Solubility of Ce₂(SO₄)₃·9H₂O (ceasium sulfate nonahydrate) at 40°C is 6.2 grams.
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I think the answer is a or c
Answer:
Postulate: Gas particles are extremely small and are far apart.
The activities can be used to demonstrate the postulate is :
<u>Observing colored gas spreading into an inverted jar placed on top of a jar containing the gas</u>
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Explanation:
colored gas spreading into an inverted jar placed on top of a jar containing the gas:
This occur because of two reasons:
1. <em><u>The Gaseous particles are largely spaced . There is large distance between the gases molecule</u></em>
<em><u>2. The gases are in continuous motion . Hence they posses very high kinetic energy . This is the reason they mixes quickly if placed in a jar.</u></em>
<em><u>This occur by the process of diffusion. </u></em>
Diffusion of Gases: The intermixing of particles from the region of high concentration to low concentration.
The coloured gas goes into the space between the gaseous molecule present in the jar.(Gases are far apart)
As soon as the coloured gas is mixed in the jar , It spread quickly by diffusion because , The gaseous particles are extremely small and are far apart.
Answer:
2
Explanation:
At the constant temp, the substance is going from a solid to a liquid and both are present (like melting ice)
Answer:
Mass = 525.36 g
Explanation:
Given data:
Mass of CO₂ formed = ?
Mass of CH₄ burned = 191 g
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O
Number of moles of CH₄:
Number of moles = mass/molar mass
Number of moles = 191 g/ 16 g/mol
Number of moles = 11.94 mol
Now we will compare the moles of CH₄ and CO₂.
CH₄ : CO₂
1 : 1
11.94 : 11.94
Mass of CO₂:
Mass = number of moles × molar mass
Mass = 11.94 mol × 44 g/mol
Mass = 525.36 g
