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MatroZZZ [7]
3 years ago
15

What is the correct name for: C3S5?

Chemistry
1 answer:
scZoUnD [109]3 years ago
5 0

Answer:

Trithioxodithiole

Explanation:

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If you are supposed to put in 2/4 a cup sugar for a recipe, can you just put in a half cup of sugar?
natta225 [31]
I would assume so.

Given \frac{2}{4}, we can simplify the fraction to \frac{1}{2}

Both would obtain the same proportions, so I don't see why putting a half cup of sugar would make things any different.

Hope this is the answer you are looking for.
8 0
3 years ago
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What is the force of a 3kg skateboard accelerating at a rate of 4m/s?
Sholpan [36]
To times 4 and 3 together for mass and acceleration then your answer would be 12, So Force= 12
7 0
3 years ago
At which condition will the entropy of a pure solid be zero?
miss Akunina [59]
The condition at which the entropy of a pure solid will be zero is<span> when a substance is at absolute zero. Absolute zero is </span><span>the lowest temperature that is theoretically possible, at which the motion of particles which constitutes heat would be minimal. It is zero on the Kelvin scale, equivalent to −273.15°C.</span>
5 0
3 years ago
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C2H6(g) + O2(g) → CO2(g) + H2O(g)
attashe74 [19]

Answer:

2C2H6 + 7O2 --> 4CO2 + 6H20

Explanation:

Balanced equation

5 0
3 years ago
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When 1000 C of charge is passed through CuSO4 solution, x g of copper is deposited. How much charge should be passed through the
Stels [109]

Number of charge = 5018 C

<h3>Further explanation</h3>

Given

1000 C of charge for x grams of copper

Required

Number of charge

Solution

Faraday's Law :

\tt W=\dfrac{e.i.t}{96500}\\\\W=\dfrac{e.Q}{96500}

For 1000 C, W = x grams

\tt x=\dfrac{1000.e}{96500}=0.0104e

For 5x grams :

\tt 5x=\dfrac{e.Q}{96500}\\\\5\times 0.0104e=\dfrac{e.Q}{96500}\\\\Q=\dfrac{96500\times 5\times 0.0104e}{e}=5018~C

6 0
3 years ago
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