Answer:
(B) 0.038 M
Explanation:
Kc = [H2][I2]/[HI]^2
Let the equilibrium concentration of H2 be y M
From the equation of reaction, mole ratio of H2 to I2 formed is 1:1, therefore equilibrium concentration of I2 is also y M
Also, from the equation of reaction, mole ratio of HI consumed to H2 formed is 2:1, therefore equilibrium concentration of HI is (1 - 2y) M
1.6×10^-3 = y×y/(1 - 2y)^2
y^2/1-4y+4y^2 = 0.0016
y^2 = 0.0016(1-4y+4y^2)
y^2 = 0.0016 - 0.0064y + 0.0064y^2
y^2-0.0064y^2+0.0064y-0.0016 = 0
0.9936y^2 + 0.0064y - 0.0016 = 0
The value of y must be positive and is obtained by using the quadratic formula
y = [-0.0064 + sqrt(0.0064^2 - 4×0.9936×-0.0016)] ÷ 2(0.9936) = 0.0736 ÷ 1.9872 = 0.038 M
Once I told a chemistry joke
I got no reaction.
What do you do with a sick chemistry teacher?
If you can't helium, and can't curium, you might as well barium.
I don't trust atoms,
I heard they make up everything
Hope I helped make ur day. :)
Answer:
What is a formation reaction? it is when a mol of a product it is formed from its elements constituents
What is standard heat of formation? the standard heat of formation or formation enthalpy, it is the amount of energy necessary for produce a mol of the product when its elements constituent react.
What is a combustion reaction? It is when a hydrocarbon reacts with oxygen and produce water a carbon dioxide
What is standard heat of combustion? It is the amount of energy released during a combustion reaction, measuring per mass or volume unit
Explanation:
A example of formation reaction is:
2H2 + O2 =2H2O
I hope my answer can help you
