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Dafna1 [17]
4 years ago
6

What is the formula of sulfurous acid? H2S HSO4 H2SO4 H2SO3

Chemistry
1 answer:
Bas_tet [7]4 years ago
6 0

The correct answer is H2SO3 I took the assignment already


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If a tube is 2.2 meters in length, how long is the the tube in feet ?​
trapecia [35]

Answer:

7.22 feet long

Explanation:

1 meter = 3.28084 feet

2.2 × 3.28084 = 7.2<u>1</u>785

= 7.22

I hope this is helpful :)

3 0
3 years ago
Which of the following is ignored when determining the relative mass of atoms? (2 points)
QveST [7]
The atomic mass is determined by the number of protons and neutrons in a atoms for example oxygen has eight protons and neutrons which gives oxygen and atomic mass of 16
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3 years ago
A tightly sealed 5.0-l flask contains 781 mm hg of ar at 19 °c. the flask is heated until the pressure is doubled. what is the t
sashaice [31]
Get on mathpapa is shows you the answer and how to explain it
3 0
3 years ago
A car is traveling at a speed of 95 mi/h. If there are 0.62137 miles (mi) in a kilometer,
SIZIF [17.4K]

Answer:

42 m/s

Explanation:

To we convert units for speed we can use dimensional analysis. First thing we do is seperate the measurement into a fraction. After this we can multiply by 1km over 0.62137 miles. We do this so that the miles cancel out.

\frac{95mi}{h} × \frac{1km}{0.62137mi} = \frac{95km}{0.62137h}

After this we can use a conversion factor and divide by 3.6.

\frac{95km}{0.62137h} ÷ 3.6 = 42 m/s

4 0
3 years ago
Place the following compounds in order of decreasing strength of intermolecular forces. I. CH3CH2CH2CH2CH2CH3 II. (CH3)3CCH3 III
Vitek1552 [10]

Explanation:

Strength of intermolecular forces depends on the number of carbon atoms present in a compound. More is the number of carbon atoms attached linearly  to each other more will be the surface area occupied by it. Hence, more is the strength of the compound.

This means that more is the branching present in a compound or lesser is the number of carbon atoms present in it then less will be the strength of intermolecular forces in the compound.

Thus, we can conclude that given compounds are placed in order of decreasing strength of intermolecular forces as follows.

CH_3CH_2CH_2CH_2CH_2CH_3 > (CH_3)_3CCH_2CH_3 > (CH_3)_3CCH_3      

7 0
4 years ago
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