Question

Select oxidation numbers for the metals in each of the following coordination compounds. (a)K[Au(OH)4] (b)Na4[Fe(Cl)6]

Answer 1

a) K[Au(OH)₄], Au = +3

b) Na₄[Fe(Cl)₆], Fe = +2

What are the general rules to find oxidation number in a coordination compound?

• All oxidation numbers in a neutral compound must equal zero.
• All oxidation numbers in an ion must sum up to the ion's charge.
• The oxidation number of a free element is zero.
• Oxidation state of Hydrogen with non metals is +1.
• Oxidation state of Hydrogen with metals is -1.
• Oxidation state of Oxygen is -2 except Fluorine and peroxides.
• Oxidation state of Fluorine is -1.

(a) K[Au(OH)₄]

Let the oxidation number of Au be X

(+1) + X + 4(-1) = 0

X + 1 - 4 = 0

X - 3 = 0

X = +3

(b) Na₄[Fe(Cl)₆]

Let the oxidation number of Fe be Y

4(+1) + Y + 6(-1) = 0

4 + Y - 6 = 0

Y - 2 = 0

Y = +2

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