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OlgaM077 [116]
1 year ago
12

Select oxidation numbers for the metals in each of the following coordination compounds. (a)K[Au(OH)4] (b)Na4[Fe(Cl)6]

Chemistry
1 answer:
Oxana [17]1 year ago
6 0

a) K[Au(OH)₄], Au = +3

b) Na₄[Fe(Cl)₆], Fe = +2

<h3>What are the general rules to find oxidation number in a coordination compound?</h3>
  • All oxidation numbers in a neutral compound must equal zero.
  • All oxidation numbers in an ion must sum up to the ion's charge.
  • The oxidation number of a free element is zero.
  • Oxidation state of Hydrogen with non metals is +1.
  • Oxidation state of Hydrogen with metals is -1.
  • Oxidation state of Oxygen is -2 except Fluorine and peroxides.
  • Oxidation state of Fluorine is -1.

(a) K[Au(OH)₄]

Let the oxidation number of Au be X

(+1) + X + 4(-1) = 0

X + 1 - 4 = 0

X - 3 = 0

X = +3

(b) Na₄[Fe(Cl)₆]

Let the oxidation number of Fe be Y

4(+1) + Y + 6(-1) = 0

4 + Y - 6 = 0

Y - 2 = 0

Y = +2

Learn more about oxidation numbers here:

brainly.com/question/12498635

#SPJ4

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3 years ago
The molar mass of glucose is 180.2 g/mol. How many grams of glucose will be produced when 132.0 g of CO2 reacts with an excess o
andriy [413]

Answer:

The mass in grams of glucose produced when 132.0 g of CO2 reacts with an excess of water is 90.1 grams

Explanation:

The chemical equation for the reaction is

6H₂O + 6CO₂  → C₆H₁₂O₆ + 6O₂

From the reaction, it is seen that 6 moles of H₂O reacts ith 6 moles of CO₂ to produce 1 mole of glucose  C₆H₁₂O₆ and 6 moles oxygen gas

The molar mass of CO₂ = 44.01 g/mol

There fpre 132.0 g contains 132.0/44.01 moles or ≅ 3 moles

However since 6 moles of CO₂ produces 1 mole of O₂, then 3 moles of CO₂ will prduce 1/6×3 or 0.5 moles of C₆H₁₂O₆

and since the molar mass (or the mass of one mole) of C₆H₁₂O₆ is 180.2 grams/mole then 0.5 mole of C₆H₁₂O₆ will have a mass of

mass of 1 mole C₆H₁₂O₆ = 180.2 g

mass of 0.5 mole C₆H₁₂O₆ = 180.2 g × 0.5 = 90.1 grams

Mass of glucose produced = 90.1 grams

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Answer:

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