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OlgaM077 [116]
1 year ago
12

Select oxidation numbers for the metals in each of the following coordination compounds. (a)K[Au(OH)4] (b)Na4[Fe(Cl)6]

Chemistry
1 answer:
Oxana [17]1 year ago
6 0

a) K[Au(OH)₄], Au = +3

b) Na₄[Fe(Cl)₆], Fe = +2

<h3>What are the general rules to find oxidation number in a coordination compound?</h3>
  • All oxidation numbers in a neutral compound must equal zero.
  • All oxidation numbers in an ion must sum up to the ion's charge.
  • The oxidation number of a free element is zero.
  • Oxidation state of Hydrogen with non metals is +1.
  • Oxidation state of Hydrogen with metals is -1.
  • Oxidation state of Oxygen is -2 except Fluorine and peroxides.
  • Oxidation state of Fluorine is -1.

(a) K[Au(OH)₄]

Let the oxidation number of Au be X

(+1) + X + 4(-1) = 0

X + 1 - 4 = 0

X - 3 = 0

X = +3

(b) Na₄[Fe(Cl)₆]

Let the oxidation number of Fe be Y

4(+1) + Y + 6(-1) = 0

4 + Y - 6 = 0

Y - 2 = 0

Y = +2

Learn more about oxidation numbers here:

brainly.com/question/12498635

#SPJ4

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3 years ago
At elevated temperature, carbon tetrachloride decomposes to its elements: CCl4(g) C(s) 2Cl2(g). At 700 K, if the initial pressur
PIT_PIT [208]

Answer:

K=0.0131M

Explanation:

Hello,

In this case, the undergoing chemical reaction turns out:

CCl_4(g) \rightleftharpoons C(s)+ 2Cl_2(g)

In such a way, by means of the mass of law action for such reaction, which is given below:

Kp=\frac{p_{Cl_2}^2}{p_{CCl_4}}

And in terms of the change x due to reaction extent:

p_{CCl_4}=p_{CCl_4}^0-x\\p_{Cl_2}=2x\\p_T=p_{CCl_4}+p_{Cl_2}=1.00-x+2x\\p_T=1.00+x

x results:

x=1.35 atm -1.00atm=0.35atm

In such a way, Kp:

Kp=\frac{(2x)^2}{1.00-x} =\frac{(2*0.35atm)^2}{1.00atm-0.35atm}=0.754atm

Nonetheless, K is asked instead of Kp, thus:

K=\frac{Kp}{(RT)^{\Delta \nu _{gas}}}

Whereas:

\Delta \nu _{gas}=2-1=1

Which is the change in the moles of gaseous species chlorine and carbon tetrachloride. Hence, we finally obtain:

K=\frac{0.754atm}{(0.082\frac{atm*L}{mol*K}*700K)^{1}}\\\\K=0.0131mol/L=0.0131M

Best regards.

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When a Lewis base id attached to the metal ion by covalent bond, then the complex ion is formed and when these complex ions are present with other ions of opposite charge or neutral charge, they will make complex compounds.
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If a space rover has a mass of 3900 kg on earth then what is its mass when it lands on mars?
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Answer:

Brainliet pls

Explanation:

390, the force of gravity is 10 N on Earth, so you would divide 3900 by 10

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