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OlgaM077 [116]
1 year ago
12

Select oxidation numbers for the metals in each of the following coordination compounds. (a)K[Au(OH)4] (b)Na4[Fe(Cl)6]

Chemistry
1 answer:
Oxana [17]1 year ago
6 0

a) K[Au(OH)₄], Au = +3

b) Na₄[Fe(Cl)₆], Fe = +2

<h3>What are the general rules to find oxidation number in a coordination compound?</h3>
  • All oxidation numbers in a neutral compound must equal zero.
  • All oxidation numbers in an ion must sum up to the ion's charge.
  • The oxidation number of a free element is zero.
  • Oxidation state of Hydrogen with non metals is +1.
  • Oxidation state of Hydrogen with metals is -1.
  • Oxidation state of Oxygen is -2 except Fluorine and peroxides.
  • Oxidation state of Fluorine is -1.

(a) K[Au(OH)₄]

Let the oxidation number of Au be X

(+1) + X + 4(-1) = 0

X + 1 - 4 = 0

X - 3 = 0

X = +3

(b) Na₄[Fe(Cl)₆]

Let the oxidation number of Fe be Y

4(+1) + Y + 6(-1) = 0

4 + Y - 6 = 0

Y - 2 = 0

Y = +2

Learn more about oxidation numbers here:

brainly.com/question/12498635

#SPJ4

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True

Explanation:

We know that the zero-point-energy of a C-D system is quite lower than the zero point energy of the C-H bond so the C-D bond is stronger.

Kinetic isotope effect refers to the change in the rate of reaction owing to a change of one of the atoms of the reactants by replacing it with one of its isotopes.

Since we know that the C-D bond is stronger than the C-H bond, when we replace hydrogen with deuterium in a reaction's rate determining step we experience a little lag in the rate of reaction. This is referred to as the kinetic isotope effect in physical organic chemistry.

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the chloride of a metal M contains 47.25% of metal 1.0 gram of metal would be displaced from a compound by 0.88 gram of another
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Answer:

The equivalent weight of M is approximately 31.8 g

The equivalent weight of N is approximately 27.98 g

Explanation:

The given parameters are;

The percentage of the the metal M in in the chloride = 47.25%

Where by the chemical formula for the metal chloride is MClₓ, we have;

47.25% of the mass of MClₓ = Mass of M = W

Therefore, we have;

\dfrac{0.4725}{W} = \dfrac{1}{W + 35.5 \cdot x}

0.4725 × (W +  35.5·x) = W

0.4725·W + 0.4725×35.5×x = W

W - 0.4725·W  = 16.77·x

0.5275·W = 16.77·x

W/x = 16.77/0.5275 = 31.799 = The equivalent weight of M

The equivalent weight of M = 31.799 ≈ 31.8 g

Given that 1 gram of M is displaced by 0.88 gram of N, then the equivalent weight of N that will displace 31.799 = 0.88 × 31.799 ≈ 27.98 g

The equivalent weight of N = 27.98 g.

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The given balanced chemical reaction is,

4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)

From the balanced chemical reaction, we conclude that

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