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1 year ago

Select oxidation numbers for the metals in each of the following coordination compounds. (a)K[Au(OH)4] (b)Na4[Fe(Cl)6]

Chemistry

1 answer:

Oxana [17]1 year ago

6 0

a) K[Au(OH)₄], Au = +3

b) Na₄[Fe(Cl)₆], Fe = +2

<h3>What are the general rules to find oxidation number in a coordination compound?</h3>

All oxidation numbers in a neutral compound must equal zero.
All oxidation numbers in an ion must sum up to the ion's charge.
The oxidation number of a free element is zero.
Oxidation state of Hydrogen with non metals is +1.
Oxidation state of Hydrogen with metals is -1.
Oxidation state of Oxygen is -2 except Fluorine and peroxides.
Oxidation state of Fluorine is -1.

(a) K[Au(OH)₄]

Let the oxidation number of Au be X

(+1) + X + 4(-1) = 0

X + 1 - 4 = 0

X - 3 = 0

X = +3

(b) Na₄[Fe(Cl)₆]

Let the oxidation number of Fe be Y

4(+1) + Y + 6(-1) = 0

4 + Y - 6 = 0

Y - 2 = 0

Y = +2

Learn more about oxidation numbers here:

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jeyben [28]

<u>Answer:</u> The correct option is 1 mole of acetic acid was required for 2 moles of sodium bicarbonate

<u>Explanation:</u>

We are given:

Average number of drops of sodium bicarbonate = 142

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$NaHCO_3+CH_3COOH\rightarrow CH_3COONa+H_2CO_3$

From the stoichiometry of the reaction:

1 mole of sodium carbonate reacts with 1 mole of acetic acid in vinegar.

Hence, the correct option is 1 mole of acetic acid was required for 2 moles of sodium bicarbonate

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4 years ago

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Alenkasestr [34]

Answer: It completely dissociates in water is a characteristic of strong acid.

Explanation:

An acid which dissociates completely to give hydrogen ions $(H^{+})$ is called a strong acid.

For example, HCl is a strong acid and it dissociates completely as follows.

$HCl \rightleftharpoons H^{+} + Cl^{-}$

Strong acids are able to conduct electricity in water as more number of ions are present in the solution as compared to the ions present in a solution of weak acid.

Strong acids increase the concentration of $H^{+}$ ions.

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