Question

Given a fixed amount of gas held at constant pressure, calculate the volume it would occupy if a 2.00 L sample were cooled from 60.0oC to 30.0oC.
a) 0.455 L
b)2.20 L
c)1.00 L
d) 1.82 L
e)4.00 L
Please give the steps

Answer 1

Answer:

1.82 L

Explanation:

We are given the following information;

• Initial volume as 2.0 L
• Initial temperature as 60.0°C
• New volume as 30.0 °C

We are required to determine the new volume;

From Charles's law;

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Where, $V_1 and V_2$ are initial and new volume respectively, while $T_1 and T_2$ are initial and new temperatures respectively;

$T_1= 333 K$

$T_2=303K$

$V_1 =2.0L$

Rearranging the formula;

$V_2=\frac{V_1T_2}{T_1}$

    $= \frac{(2.0L)(303K)}{333K} \\=1.820 L$

Therefore, the new volume that would be occupied by the gas is 1.82 L