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lora16 [44]
1 year ago
6

What is the purpose of adding 0. 1% agar to the trypticase nitrate broth when conducting the nitrate reduction test?.

Chemistry
1 answer:
PilotLPTM [1.2K]1 year ago
5 0

Agar is used to assist establish an anaerobic environment that promotes nitrate reduction.

Nitrate Reduction test:

  • The nitrate in the broth is converted to nitrite by organisms that can produce the nitrate reductase enzyme, which can then be further converted to nitric oxide, nitrous oxide, or nitrogen.
  • Anaerobic respiration and denitrification are two processes that can convert nitrate to a variety of compounds.
  • While denitrification only reduces nitrate to molecular nitrogen, anaerobic respiration employs nitrate as the bacterium's final electron acceptor, reducing it to a range of chemicals.
  • The nitrate reduction test is based on the detection of nitrite and its capacity to produce a red precipitate (prontosil), which is a water-soluble azo dye, when it combines with sulfanilic acid to create a complex (nitrite-sulfanilic acid).

Learn more about the Nitrate reduction test with the help of the given link:

brainly.com/question/11181586

#SPJ4

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8. The best way to obtain pure, solid household salt from a solid mixture of household salt and sand is to:
dedylja [7]

The best way to obtain pure, solid household salt from a solid mixture of household salt and sand is to "add water, stir, filter and evaporate the filtrate".

<u>Option: C</u>

<u>Explanation:</u>

The salt and sand can be separated on the basis of solubility, as we know the salt is chemically known as sodium chloride, which have good solubility in water. The most general method is the mixture is taken into a flask or beaker and water is added with stirring, where salt get dissolved and sand remain as it is, because NaCl is capable enough to form hydrogen bonding with water, while sand have absence of such property. Then this solution containing insoluble sand is filtered by using filter paper. The sand is received in filter paper while filtrate in beaker is evaporated by boiling it in order to receive salt as residue.

8 0
3 years ago
A solution has a pH of 2.5. What is its [OH-] ?
gulaghasi [49]
POH=14-pH=14-2.5=11.5 pH=-log[H+] 2.5=-log [H+] [H+]=10^-5/2 [OH-]=10^(14-5/2)=10^23/2
8 0
2 years ago
Question 6 of 10
Levart [38]

Answer:

C. Solids made of molecules

3 0
2 years ago
Why doesn’t a broken wineglass spontaneously fix itself, from a thermodynamic point of view?
Anarel [89]
C. Fixing a wineglass requires a large decrease in entropy.
4 0
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Read 2 more answers
2 NaOH (s) + CO2(g) → Na2CO3 (s) + H20 (I)
Paha777 [63]
<h3>Answer:</h3>

16.7 g H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2NaOH (s) + CO₂ (g) → Na₂CO₃ (s) + H₂O (l)

[Given] 1.85 mol NaOH

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol NaOH → 1 mol H₂O

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up:                               \displaystyle 1.85 \ mol \ NaOH(\frac{1 \ mol \ H_2O}{2 \ mol \ NaOH})(\frac{18.02 \ g \ H_2O}{1 \ mol \ H_2O})
  2. Multiply/Divide:                 \displaystyle 16.6685 \ g \ H_2O

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

16.6685 g H₂O ≈ 16.7 g H₂O

6 0
2 years ago
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