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netineya [11]
3 years ago
7

A gas of unknown molar mass was allowed to effuse through a small opening under constant pressure conditions. It required 986 s

for 1.00 L of this gas to effuse. Under identical experimental conditions it required 811 s for 1.00 L of chlorotrifluoromethane (CClF3) gas to effuse. Calculate the molar mass of the unknown gas . (Remember that the faster the rate of effusion, the shorter the time required for effusion; that is, rate and time are inversely proportional.)
Chemistry
1 answer:
Kobotan [32]3 years ago
6 0

Answer:

The molar mass of the unknown gas is 154.4 g/mol

Explanation:

Step 1: Data given

It takes 986 seconds for an unknown gas to effuse

It takes 811 seconds for chlorotrifluoromethane (CClF3) gas to effuse

Molar mass of chlorotrifluoromethane (CClF3) = 104.46 g/mol

Step 2: Calculate the molar mass of the gas

t1/t2/ √(M1/M2)

⇒with t1 = the time needed for the unknown gas to effuse = 986 seconds

⇒with t2 = the time needed for CClF3 to effuse = 811 seconds

⇒with M1 = the molar mass of the unknown gas = TO BE DETERMINED

⇒with M2 = the molar mass of CClF3 = 104.46 g/mol

986/811 = √(M1/104.46)

(986/811)² = M1 / 104.46

M1 = 154.4 g/mol

The molar mass of the unknown gas is 154.4 g/mol

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Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 9.32 g of ethane is
Pie

Answer:

There will remain 8.06 grams of ethane

Explanation:

Step 1: Data given

Mass of ethane = 9.32 grams

Mass of oxygen = 12.0 grams

Molar mass ethane = 30.07 g/mol

Molar mass oxygen = 32.00 g/mol

Step 2: The balanced equation

2 C2H6 + 7 O2 → 4 CO2 + 6 H2O

Step 3: Calculate moles ethane

Moles ethane = mass ethane / molar mass ethane

Moles ethane = 9.32 grams / 30.07 g/mol

Moles ethane = 0.3099 moles

Step 4: Calculate moles oxygen

Moles oxygen = 12.0 grams / 32.0 g/mol

Moles oxygen = 0.375 moles

Step 5: Calculate the limiting reactant

For 2 moles ethane we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

O2 is the limiting reactant. It will completely be consumed ( 0.375 moles)

Ethane is in excess. There will react 2/7 * 0.375 = 0.107 moles

There will remain 0.375 - 0.107 = 0.268 moles

Step 6: Calculate mass ethane

Mass ethane = moles ethane * molar mass ethane

Mass ethane = 0.268 moles * 30.07 g/mol

Mass ethane = 8.06 grams

There will remain 8.06 grams of ethane

7 0
3 years ago
1. Caused by movement of rocks<br>below the surface. is Called?​
valentina_108 [34]
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KiRa [710]

Answer:

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7 0
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An atom has 9 electrons and 9 protons at the start. If it loses 2 electrons, the net charge on the atom will be 8-2-2+8+. If the
Mrrafil [7]

Answer: 1) p⁺ = 22; number of protons.

e⁻ = 19 - 1 = 18; number of electrons.

Net charge is +4, because atom has 4 protons more than electrons.

Proton is a subatomic particle with a positive electric charge of +1e elementary charge.

2) p⁺ = 22; number of protons.

e⁻ = 19 + 3 = 22; number of electrons.

Net charge is 0 (neutral charge), because atom has same number of protons and electrons.

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4 0
3 years ago
The reactants of two chemical equations are listed. Equation 1: PbNO3 + Mg Equation 2: PbNO3 + KI Based on the type of reaction,
Vika [28.1K]

Answer:

Equation 2, because K being more reactive, exchanges position with Pb in PbNO3.

Explanation:

Hello there!

In this case, according to the given reactions, it is possible to realize that according to the reactivity series, since K is is group 1A of alkali metals, we infer it is by far more reactive than magnesium, for that reason last two choices can be easily discarded. Now, considering equation 2, it would be necessary to complete it to figure out the correct option:

Pb(NO_3)_2 + KI \rightarrow PbI_2+KNO_3

Whereas it can be seen that potassium exchanges position with Pb according to the double displacement reaction; therefore, the correct answer is "Equation 2, because K being more reactive, exchanges position with Pb in PbNO3".

Best regards!

8 0
3 years ago
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