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Natali [406]
3 years ago
10

What is the state of the substance at room temperature (20°c)

Chemistry
1 answer:
soldier1979 [14.2K]3 years ago
5 0

Answer:

dez nuts. the forth quauter in ur girls buttr

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3 years ago
Boron trifluoride gas is collected at 2.0 degree C in an evacuated flask with a measured volume of 15.0 L. When all the gas has
IgorC [24]

Answer:

Moles of boron trifluoride gas that were collected = 11.6 mol

Mass of boron trifluoride gas that were collected = 787 g

Explanation:

Given that:

Temperature = 2.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (2.0 + 273.15) K = 275.15 K

V = 15.0 L

Pressure = 0.130 atm

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L atm/ K mol  

Applying the equation as:

0.130 atm × 15.0 L = n ×0.0821 L atm/ K mol  × 275.15 K

⇒n = 11.6 mol

<u>Thus, Moles of boron trifluoride gas that were collected = 11.6 mol </u>

Molar mass of boron trifluoride gas = 67.82 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

11.6\ mole= \frac{Mass}{67.82\ g/mol}

<u>Mass of boron trifluoride gas that were collected = 787 g</u>

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3 years ago
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Hello
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