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Tems11 [23]
1 year ago
13

Part a a calorimeter consists of an aluminum cup inside of an insulated container. The cup is weighed on a top-loading balance a

nd is found to have a mass of 31. 91 g. A reaction is conducted in the calorimeter, raising the temperature from 21. 2 c to 26. 1 c what is the change in heat q for the aluminum cup in units of j? aluminum has a specific heat of 0. 903 j 1 ? 1 write your answer to the correct number of significant figures.
Physics
1 answer:
MrRa [10]1 year ago
4 0

The change in heat q for the aluminum cup is 141 J.  

<h3>What is Specific heat?</h3>

A substance's heat capacity is the amount of heat needed to increase its overall temperature by one degree. The heat capacity is known as the specific heat capacity or the specific heat if the substance's mass is unity.

change in heat -

The amount of heat Q that is transported to create a temperature shift depends on the substance and phase involved, the mass of the system, and the magnitude of the temperature change. (A) The temperature change and the amount of heat transported are directly inversely related.

The answer's sign dig is determined by a calculation's lowest sign digits.

The solution will need 3 digits because the temperatures are provided with 3 significant digits and the specified heat has 3 significant digits (the mass has 4 significant digits).

31.91 g   * 0.903 J/g-C  *  (26.1 - 21.2 C) = 141 J

to learn more about Specific Heat go to - brainly.com/question/21406849

#SPJ4

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Can you go around a curve with a constant acceleration?
SashulF [63]

No , u can't go around a curve with constant acceleration

Explanation:

If an object is moving along a curved path ,there could be several forces acting on it.

5 0
2 years ago
A tiger covers a distance of 600 m in 15 minutes what is a speed of a tiger?​
aliya0001 [1]

Answer: 2.4 km/hr

Explanation:

Distance = 600m

Time= 15 minutes = 15 x 60 second/minute = 900 seconds

Speed =  \frac{Distance}{Time}  =  \frac{600}{900}  = \frac{2}{3} m/sec

⇒ \frac{2}{3} x \frac{18}{5} = 2.4 km/hr (1 m/sec = 3.6 km/hr)

5 0
3 years ago
When a particular hanging mass is suspended from the string, a standing wave with two segments is formed. When the weight is red
ahrayia [7]

Solution :

Mass is varied keeping frequency constant.

Wavelength, λ  $=\frac{2l}{n}$

where length of spring = l

           number of segments = n

Velocity, v = λ x f

                 = $\sqrt{\frac{T}{\mu}}$

$\mu $ =  mass density, T = tension in string

$T=\frac{4 \mu l^2f^2}{n^2}$

$T=mg = \frac{4 \mu l^2f^2}{n^2}$  , n = 2

$T = (m-2.2)g = \frac{4 \mu l^2f^2}{n^2}, n = 5$

$\Rightarrow \frac{m}{m-2.2}=\frac{25}{4}$

$\Rightarrow m = 2.619\ kg$

Therefore, μ = 0.002785 kg/ m

Frequency is varied keeping T constant

$T=\frac{4 \mu l^2f^2}{n^2}, f=60 , \ \  n = 2$

$T=\frac{4 \mu l^2f^2}{n^2}, f=? , \ \  n = 7$

$\Rightarrow \frac{60^2}{4}=\frac{f^2}{49}$

f = 210 Hz

8 0
3 years ago
A bus initially at rest accelerated of 4m/S2 at the end of 10 second find average velocity​
elixir [45]

Answer:

V = 20m/s

Explanation:

Given the following data;

Acceleration = 4m/s²

Time = 10 secs

Initial velocity = 0m/s (since it's at rest).

To find the average velocity, we would use the first equation of motion;

V = U + at

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Substituting into the equation, we have;

V = 0 + 4*10

V = 40m/s

To find the average velocity;

Average velocity = (U + V)/2

Average velocity = (0 + 40)/2

Average velocity = 40/2

Average velocity = 20m/s

6 0
3 years ago
You've recently read about a chemical laser that generates a 20.0-cm-diameter, 22.0 MW laser beam. One day, after physics class,
Setler [38]

Answer:

0.3847 m/s

Explanation:

I = Intensity = \dfrac{P}{A}=\dfrac{P}{\pi r^2}

d = Diameter = 20 cm

r = Radius = \dfrac{d}{2}=\dfrac{20}{2}=10\ cm

c = Speed of light = 3\times 10^8\ m/s

s = Distance = 100 m

P = Power = 22 MW

Pressure due to the laser is given by

P_r=\dfrac{I}{c}\\\Rightarrow P_r=\dfrac{P}{Ac}\\\Rightarrow P_r=\dfrac{P}{\pi r^2c}\\\Rightarrow P_r=\dfrac{22\times 10^{6}}{\pi 0.1^2\times 3\times 10^8}\\\Rightarrow P_r=2.33427\ N/m^2

Force is given by

F=P_rA\\\Rightarrow F=2.33427\times \pi 0.1^2\\\Rightarrow F=0.07333\ N

Acceleration is given by

a=\dfrac{F}{m}\\\Rightarrow a=\dfrac{0.07333}{99}\\\Rightarrow a=0.00074\ m/s^2

Speed of the block would be

v=\sqrt{2as}\\\Rightarrow v=\sqrt{2\times 0.00074\times 100}\\\Rightarrow v=0.3847\ m/s

The speed of the block is 0.3847 m/s

5 0
3 years ago
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