Answer:
satellites and weather fronts
Answer:
-0.233 m left of diverging lens and ( 0.12 - 0.233 ) = -113 m left of conversing
and
0.023 m right of diverging lens
Explanation:
given data
focal length f2 = 14 cm = -0.14 m
Separation s = 12 cm = 0.12 m
focal length f1 = 21 cm = 0.21 m
distance u1 = 38 cm
to find out
final image be located and Where will the image
solution
we find find image location i.e v2
so by lens formula v1 is
1/f = 1/u + 1/v ...............1
v1 = 1/(1/f1 - 1/u1)
v1 = 1/( 1/0.21 - 1/0.38)
v1 = 0.47 m
and
u2 = s - v1
u2 = 0.12 - 0.47
u2 = -0.35
so from equation 1
v2 = 1/(1/f2 - 1/u2)
v2 = 1/(-1/0.14 + 1/0.35)
v2 = -0.233 m
so -0.233 m left of diverging lens and ( 0.12 - 0.233 ) = -113 m left of conversing
and
for Separation s = 45 cm = 0.45 m
v1 = 1/(1/f1 - 1/u1)
v1 =0.47 m
and
u2 = s - v1
u2 = 0.45 - 0.47 =- 0.02 m
so
v2 = 1/(1/f2 - 1/u2)
v2 = 1/(-1/0.14 + 1/0.02)
v2 = 0.023
so here 0.023 m right of diverging lens
Joule
The standard unit for kinetic energy is the joule (J). The joule is the standard unit for energy in general. Other units for energy include the newton-meter (Nm) and the kilogram meter squared over seconds squared (kg m2/s2).
Answer:
ma+mgsinh0+f=F∴(25)(0.75)+(25)(10)sinh0+μkN=F∴18.75+(250)(0.6h)+μk(mgcosh0=F⟹18.75+150+μk((25)(10)(0.76))=500∴168.75+μk(190)=500⟹μk(190)=331.25⟹μk=1.74
Explanation:
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Below is the solution:
<span>centripetal accel = 1.5*g
ω²r = 1.5*9.8m/s²
ω² * 8m = 14.7 m/s²
ω = 1.36 rad/s * 1rev/2πrads * 60s/min = 12.9 rpm</span>
