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a_sh-v [17]
3 years ago
11

Blake and Sandra are having a rummage sale. Blake drags 3 boxes a distance of 10 meters each. He exerts a force of 20 newtons on

each box. Sandra drags 4 boxes a distance of 12 meters each. She exerts a force of 15 newtons on each box. Blake takes 2 minutes to complete his work. Sandra takes 4 minutes.
Blake does ____ work than Sandra. Blake’s power ____ is than Sandra’s power.

(Hint: Use W = Fd and P = w/t.)
Physics
2 answers:
vampirchik [111]3 years ago
5 0
For Blake:

3 boxes at a distance of 10 meters each, each box weighs 20 N

Work done by Blake = 3 * 10m * 20N
                                 = 600 J
Power = 600 J/ 2 min
           = 300 J/min

For Sandra:

4 boxes, 15 N each at a distance of 12 meters each. 

Work done by Sandra = 4 * 15 N *12m
                                    =  720 J
Power = 720 J/ 4 min
           = 180 J/min

Blake does less work than Sandra. 
Blake's power is more than Sandra's.
stiv31 [10]3 years ago
3 0

Answer:

Blake does  less  work than Sandra. Blake’s power is  

more  than Sandra’s power.

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Answer:

a)   x_average = ∑ x_{i} / n , b) Δx_{i} = x_{i} –x_average,

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Explanation:

Some definitions are requested

a) the average value is the sum of all the values ​​divided by the number of them, if the uncertainties are random, this is the closest value to the real one

       x_average = ∑ x_{i} / n

b) The deviation from the mean value or absolute error is the measured value minus the average value

       Δx_{i} = x_{i} –x_average

c) is the average value of the deviations

        Δx_average = ∑ Δx_{i} / n

d) It is a measure of the dispersion of the values ​​with respect to their average value, it takes the worst of all cases, widely used for large numbers of data

          σ = √(1/n-1  ∑ Dx_{i}² )

Experimental results should be given as follows

  Average value ± uncertainty and the standard deviation

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  σ

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3 years ago
You push the ball with aforce of 22.8N which induces a -2.3N frictional force. What is the net force while you push?
inna [77]
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A tree loses water to the air by the process of transpiration at the rate of 110 g/h. This water is replaced by the upward flow
Ksivusya [100]

Answer:

The answer is 1.87nm/s.

Explanation:

The 110g/hr  water loss must be replaced by 110g/hr of sap. 110g of sap corresponds to a volume of  

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taking the derivative of both sides we get:

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\boxed{v =1.875*10^{-9}m/s = 1.875nm/s}

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Answer:

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