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Zina [86]
3 years ago
6

A forklift pushes a box with a force of 500 N across the floor for a distance of 5.0 m, then turns around and pushes with the sa

me force 5.0 m back to its original position. How much work did the forklift do during this time?
Physics
1 answer:
yanalaym [24]3 years ago
4 0

Answer:

5,000J

Explanation:

Work = Force x Distance

Distance back and forth is canceled out, so either the answer is + or -

5.0m + 5.0m = 10.0m

500N x 10.0m = 5,000J

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What are the <br>difference between clinical and laboratory thermometer?<br><br><br>​
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3 years ago
In 1994, Leroy Burrell of the United States set what was then a new world record for the men’s 100 m run. He ran the 1.00  102
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61.33 Kg

Explanation:

From the question given above, the following data were obtained:

Distance = 1×10² m

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Velocity = 10.53 m/s

Finally, we shall determine the mass of Leroy Burrell. This can be obtained as follow:

Kinetic energy (KE) = 3.40×10³ J

Velocity (v) = 10.53 m/s

Mass (m) =?

KE = ½mv²

3.40×10³ = ½ × m × 10.53²

3.40×10³ = ½ × m × 110.8809

3.40×10³ = m × 55.44045

Divide both side by 55.44045

m = 3.40×10³ / 55.44045

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<h2>Derived quantities are based on fundamental quantities, and they can be given in terms of fundamental quantities.</h2>

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