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1 year ago

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A 16-cm-diameter circular loop of wire is placed in a 0. 64-t magnetic field. part a when the plane of the loop is perpendicular

to the field lines> What is the magnetic flux through the loop?

1 answer:

Gnoma [55]1 year ago

7 0

128.72 Wb is the magnetic flux through the loop

A measurement of the total magnetic field that traverses a specific area is called magnetic flux.

It is a helpful tool for explaining how the magnetic force affects things inhabiting a certain area.

The precise area selected will determine how magnetic flux is measured.

Given,

Diameter of Circular Loop = 16 cm

The radius of Circular Loop = 8 cm

Area of Circular loop = πr² = 22/7 × 8 × 8

= 201.14 cm²

Magnetic field = 0.64 T

The angle between area vector and the field lines = 0°

Formula used :

Magnetic flux (Ф) = B.Acosθ

where B = Magnetic field of a circular loop of wire

A = Area of a circular loop of wire

θ = Angle between area vector and the field lines

Magnetic flux = 0.64 × 201.14 × 1

= 128.72 Wb

Learn more about Magnetic flux here brainly.com/question/15841876

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mars1129 [50]

Answer:

(1) Initial speed, $u=0$

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Explanation:

(1)

Given,

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Time, $t=3.62second$

It is given that drag racer started at rest.

So Initial speed, $u=0$

Using Newton's second equation of motion,

$S=ut+\frac{1}{2}at^2\\300=0+\frac{a\times3.62^2}{2} \\a=45.79m/s^2$

Newton's first equation of motion,

$v=u+at\\=0+45.79\times3.62\\=165.76 m/s$

So, Final speed, $v=165.76m/s$

Average speed is defined as totle distance divided by totle time.

$v_a_v_g=\frac{S}{t}\\=\frac{300}{3.62} \\=82.87m/s$

So, Average speed, $v_a_v_g=82.87m/s$

(2)

Gravitation: It is the natural phenomenon in which two different bodies attract each other by virtue of their masses.

According to Newton's law of gravitation, the force of attraction between two bodies is directly proportional to the masses of the bodies and inversely proportional to square of distance between centers of mass of the bodies.

$F_g\propto\frac{m_1m_2}{r^2} \\F_g=G\frac{m_1m_2}{r^2}$ where $G$ is constant of proportionality and known as gravitation constant.

Given,

Mass of Jupiter, $m_1=1.9\times10^2^7kg$

Mass of Ganymede, $m_2=1.48\times10^2^3kg$

Distance between their centers of mass, $r=1.21\times10^1^2meter$

$F_g=G\frac{m_1m_2}{r^2}\\=\frac{6.67\times10^-^1^1\times1.9\times10^2^7\times1.48\times10^2^3}{(1.21\times10^1^2)^2} \\=12.8\times10^1^5N$

So, Force of gravity, $F_g=12.8\times10^1^5N$

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san4es73 [151]

La aceleración que adquiere el cuerpo de 0.5Kg es:

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3 years ago

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frez [133]

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