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labwork [276]
3 years ago
15

A piano of mass 852 kg is lifted to a height of 3.5 m. How much gravitational potential energy is added to the piano? Accelerati

on due to gravity is g = 9.8 m/s2 O A. 102,282 J O B. 29,224J O C. 2982 J O D. 304.3J SUSM​
Physics
1 answer:
slega [8]3 years ago
6 0

Answer:

29223.6J

Explanation:

Given parameters:

Mass of Piano = 852kg

Height of lifting  = 3.5m

Unknown:

Gravitational potential energy  = ?

Solution:

The gravitational potential energy of a body can be expressed as the energy due to the position of a body;

  G.P.E  = mgh

m is the mass

g is the acceleration due to gravity

h is the height

 Now insert the given parameters and solve;

   G.P.E  = 852 x 9.8 x 3.5 = 29223.6J

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Vector A has magnitude 8.00 mm and is in the xy-plane at an angle of 127∘ counterclockwise from the +x–axis (37∘ past the +y-axi
Ilia_Sergeevich [38]

Answer:

-75.35°

Explanation:

Let C be the sum of the two vectors A and B. Hence, we can write the following  

A_{x} +B_{x} =C_{x} ......(1)\\A_{y} +B_{y} =C_{y} ......(2)

but since the vector C is in the -y direction, C_{x}  = 0 and C_{y} = —12 m.  

Thus  

B_{x} =-A_{x} =-[-Acos(180-127)]=(8)*cos(53)\\B_{x} =4.81m

similarly, we can determine B_{y} by rearranging equation (1)  

 B_{y} =C_{y} -A_{y} =-12m-[(8)*sin(53)\\B_{y} =-18.4m

so the magnitude of B is

B=\sqrt{B_{x}^2+B_{y}^2  } \\B=19m

Finally, the direction of B can be calculated as follows  

Ф=tan^{-1} (\frac{B_{y} }{B_{x} } )\\=-75.35

hence the vector B makes an angle of 75.35 clockwise with + x axis

8 0
4 years ago
How to determine the center of gravity of a lamina​
goldenfox [79]
Take a lamina with three holes near the periphery of the lamina, now suspend the lamina through them, one by one. Draw a line of equilibrium for each suspension point. The point of intersection of these three lines would be the centre of gravity.
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2 years ago
Which statement best describes why an island food web could be considered a closed system
iris [78.8K]

B. Energy enters and exits the system matter does not

Explanation:

In thermodynamics, there are three types of system:

  • Open system: it is a system that exchanges both matter and energy with the surroundings - an example is an open bottle
  • Closed system: it is a system that exchanges only matter with the surroundings, while energy cannot enter and exit the system - an example is a closed bottle (air cannot enter/exit the bottle, but heat can be exchanged through the walls of the bottle)
  • Isolated system: it is a system that cannot exchange matter or energy with the surroundings - an example is a sealed thermic container (heat cannot pass through the walls)

In this problem, we are asked to identify which statement best describes the island food web as a closed system: based on the definitions above, we can say that the correct option is

B. Energy enters and exits the system matter does not

Learn more about thermodynamics:

brainly.com/question/4759369

brainly.com/question/3063912

brainly.com/question/3564634

#LearnwithBrainly

6 0
3 years ago
Which of the following does notaccurately describe the forces that exist with an atom? 
natima [27]
The believe the answer to this is B
8 0
3 years ago
A car's bumper is designed to withstand a 6.84 km/h (1.9-m/s) collision with an immovable object without damage to the body of t
den301095 [7]

Answer:

F = 5.256 x 10^{3} N

Explanation:

From the work energy theorem we know that:

The net work done on a particle equals the change in the particles kinetic energy:

W = F.d, ΔK =\frac{1}{2} mv^{2}_{f}   - \frac{1}{2} mv^{2}_{i}  , F.d = \frac{1}{2}mv^{2}_{f} -\frac{1}{2} mv^{2}_{i}

where:

W = work done by the force

F = Force

d = Distance travelled

m = Mass of the car

vf, vi = final and initial velocity of the car

kf, ki = final and initial kinetic energy of the car

Given the parameters;

m = 830kg

vi = 1.9 m/s

vf = 0 km/h

d = 0.285 m

Inserting the information we have:

F.d = \frac{1}{2} mv^{2}_{f}   - \frac{1}{2} mv^{2}_{i}

F = \frac{\frac{1}{2} mv^{2}_{f}   - \frac{1}{2} mv^{2}_{i} }{d}

F = \frac{ 0   - \frac{1}{2}  X830 X 1.9^{2} }{0.285}

F = 5.256 x 10^{3} N

3 0
3 years ago
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