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3 years ago

13

A street lamp weighs 150N. It is supported by two wires that form an angle of 120° with each other. The tensions in each wire ar

e equal. What is the tension in each wire?

1 answer:

____ [38]3 years ago

4 0

Answer:

60

so you take 120÷2 wires

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11. You sit at the outer rim of a Ferris wheel that rotates 2 revolutions per minute (RPM). What would your rotational speed be

aalyn [17]

If you are instead clinging to a position halfway from the center to the outer rim of the Ferris wheel, YOUR ROTATIONAL SPEED WILL STILL BE 2 REVOLUTION PER MINUTE.
This is because, every part of the wheel is moving with the same speed, so it does not matter where you sit on the wheel, the rotation per minute will still be the same. It is just like travelling inside a motor car, it does not matter whether you are sitting in the front passenger seat or at the back, the speed of the car remains the same.

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3 years ago

What's the formula for frequency?

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Answer:

assuming ur speaking about chemistry

c=frequency×wavelength

or

energy=frequency×h

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3 years ago

A box on a table has these forces acting on it

umka21 [38]

Answer:

greater than 10 n

Explanation:

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3 years ago

A rock is tossed straight up from the ground with a speed of 21 m/s . When it returns, it falls into a hole 10 m deep.a.) What i

Arte-miy333 [17]

(a) 25.2 m/s

Let's take the initial vertical position of the rock as "zero" (reference height).

According to the law of conservation of energy, the speed of the rock as it reaches again the position "zero" after being thrown upwards is equal to the initial speed of the rock, 21 m/s (in fact, if there is no air resistance, no energy can be lost during the motion; and since the kinetic energy depends only on the speed of the rock:

$K=\frac{1}{2}mv^2$

and the gravitational potential energy of the rock has not changed, since the rock has returned into its initial position, it means that the speed of the rock should be the same)

This means that we can only analyze the final part of the motion, the one in which the rock falls into the 10 m hole. Since it is a free fall motion, we can find the final speed by using

$v^2 = u^2 + 2gd$

where

u = 21 m/s is the initial speed of the rock as it enters the hole

g = 9.8 m/s^2 is the acceleration due to gravity

d = 10 m is the depth of the hole

Substituting,

$v=\sqrt{u^2 +2gd}=\sqrt{(21 m/s)^2+2(9.8 m/s^2)(10 m)}=25.2 m/s$

(b) 4.72 s

The vertical position of the rock at time t is given by

$y(t) = v_y t - \frac{1}{2}gt^2$

where

$v_y = 21 m/s$ is the initial vertical velocity

Substituting y(t)=-10 m, we can then solve the equation for t to find the time at which the rock reaches the bottom of the hole:

$-10 = 21 t - \frac{1}{2}(9.8)t^2\\10+21 t -4.9t^2 = 0$

which has two solutions:

t = -0.43 s --> negative, so we discard it

t = 4.72 s --> this is our solution

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4 years ago

A garbage truck crashes head-on into a Volkswagen and the two come to rest in a cloud of flies. Which experiences the greater fo

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The volkswagon experiences a greater force as it was hit by a larger object that had a larger mass than itself

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3 years ago