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3 years ago

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A street lamp weighs 150N. It is supported by two wires that form an angle of 120° with each other. The tensions in each wire ar

e equal. What is the tension in each wire?

1 answer:

____ [38]3 years ago

4 0

Answer:

60

so you take 120÷2 wires

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Two astronauts are 2.00 m apart in their spaceship. One speaks to the other. The conversation is transmitted to earth via electr

Eduardwww [97]

Answer:

$D=1693742.7m$

Explanation:

For sound waves we have v=d/t where v is the speed of sound and d the distance between the astronauts, while for electromagnetic waves we have c=D/t where c is the speed of light and D the distance between the spaceship and Earth. <em>We have written both times as the same</em> because is what is imposed by the problem, so we have t=d/v=D/c, which means:

$D=\frac{dc}{v}$

And for our values:

$D=\frac{(2m)(299792458m/s)}{354m/s}=1693742.7m$

5 0

3 years ago

What’s the ion of element iodine ?

Kipish [7]

The ion of idodine is neutral

3 0

3 years ago

Types of cell combination? in electricity

Grace [21]

Answer:

Series and Parallel

7 0

3 years ago

Two harmonic waves traveling in opposite directions interfere to produce a standing wave described by y = 3 sin (2x) cos 5t wher

Nostrana [21]

Answer:

The wavelength of the interfering waves is 3.14 meters.

Explanation:

Given that,

The equation of standing wave that is formed by interfering two harmonic waves (travelling opposite direction) is given by :

$y=3\ sin(2x)\ cos(5t)$ ........(1)

The general equation of standing wave is given by :

$y=2A\ sin(kx)\ cos(\omega t)$ ..............(2)

On comparing equation (1) and (2), we get :

k = 2

We know that,

$\dfrac{2\pi}{\lambda}=k$

$\dfrac{2\pi}{\lambda}=2$

$\lambda=3.14\ m$

So, the wavelength of the interfering wave is 3.14 meters. Hence, this is the required solution.

8 0

3 years ago

Help me pleaseeeeeeddd

Vladimir79 [104]

Answer:

Explanation:

a )

According to graph the object moves with constant velocity of 10 m /s during first 8 s and then its velocity changes to - 5 m /s from 8 th second upto 12 th second .

Initial displacement = 8 m

displacement during 8 s = velocity x time

= 8 x 10 = 80 m

total displacement = 88 m

b )

displacement during period from 8 th to 12 th s

= - 5 x 4 = - 20 m

total displacement after 12 s

= 88 - 20 = 68 m

c ) average speed = total distance covered during 12 s / total time

= (80 + 20) / 12

= 8.33 m /s

average velocity = total displacement during 12 s / total time

= 80 - 20 / 12

= 60 / 12

= 5 m /s .

7 0

3 years ago