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Sergeu [11.5K]
3 years ago
7

If your chunk of gold weighed 1 N in which case would you have the largest mass of gold?

Physics
1 answer:
kotykmax [81]3 years ago
3 0
Ah ha !  Very interesting question.
Thought-provoking, even.

You have something that weighs 1 Newton, and you want to know 
the situation in which the object would have the greatest mass.

          Weight = (mass) x (local gravity)

          Mass  =  (weight) / (local gravity)

          Mass  =  (1 Newton) / (local gravity)

"Local gravity" is the denominator of the fraction, so the fraction
has its greatest value when 'local gravity' is smallest.  This is the
clue that gives it away.

If somebody offers you 1 chunk of gold that weighs 1 Newton,
you say to him:

   "Fine !  Great !  Golly gee, that's sure generous of you.  
But before you start weighing the chunk to give me, I want you
to take your gold and your scale to Pluto, and weigh my chunk
there.   And if you don't mind, be quick about it."

The local acceleration of gravity on Pluto is  0.62 m/s² ,
but on Earth, it's 9.81 m/s.

So if he weighs 1 Newton of gold for you on Pluto, its mass will be
1.613 kilograms, and it'll weigh 15.82 Newtons here on Earth. 

That's almost 3.6 pounds of gold, worth over $57,000 !


It would be even better if you could convince him to weigh it on
Halley's Comet, or on any asteroid.  Wherever he's willing to go
that has the smallest gravity.  That's the place where the largest
mass weighs 1 Newton.

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When an object loses electrons, it acquires a(n) ____________________ electric charge?
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It acquires a positive electric charge.
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উপরোক্ত ঘটনা ভরবেগের সংরক্ষণ সূত্র সমর্থন করে কি? গাণিতিক বিশ্লেষণের মাধ্যমে মতামত দাও।
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truelol

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same

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3 0
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The intensity of sound waves is linearly proportional to ?
Airida [17]

(1) The intensity of a sound wave is linearly proportional to the change in the pressure squared.

(2) You are able to hear sounds from farther away on a cool night because sound waves are refracted toward<u> </u><u>warmer air </u><u>near the ground.</u>

(3) When the trough of one wave collides at the same time & place of the crest of an identical wave, destructive interference occurs.

(4) The time taken for the heater to provide the energy is 300 secs.

(5) The total amount of heat provided to the ice sample is 7,980 cal.

(6) The amount of heat required to increase the temperature of water is 33,472 J.

<h3>Intensity of sound</h3>

The intensity of a sound wave is linearly proportional to the change in the pressure squared and inversely proportional to the density and the speed.

<h3>Refraction of sound waves</h3>

You are able to hear sounds from farther away on a cool night because sound waves are refracted toward warmer air near the ground.

<h3>Destructive inference</h3>

When the trough of one wave collides at the same time & place of the crest of an identical wave, destructive interference occurs.

<h3>Time taken for the heater to provide the energy</h3>

E = Power x Time

t = E/P

t = 60,000/200

t = 300 secs

<h3>Total amount of heat provided to the ice sample</h3>

Q = 79.8 cal/g x 100 g

Q = 7,980 cal

<h3>Amount of heat required to increase the temperature of water</h3>

Q = 0.1 kg x 4184 J/kgC x (100 - 20)

<em>When water vapor condense into liquid water, temperature = 100⁰C</em>

Q = 33,472 J

Thus, the intensity of a sound wave is linearly proportional to the change in the pressure squared.

  • You are able to hear sounds from farther away on a cool night because sound waves are refracted toward<u> </u><u>warmer air </u><u>near the ground.</u>
  • When the trough of one wave collides at the same time & place of the crest of an identical wave, destructive interference occurs.
  • The time taken for the heater to provide the energy is 300 secs.
  • The total amount of heat provided to the ice sample is 7,980 cal.
  • The amount of heat required to increase the temperature of water is 33,472 J.

Learn more about intensity of sound here: brainly.com/question/17062836

#SPJ1

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