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Diano4ka-milaya [45]
3 years ago
8

words are written in straight lines forwards backwards up down and diagonally when you find the word circle or highlight it. onc

e you have found all the words define each​

Chemistry
1 answer:
Marianna [84]3 years ago
5 0

Can I know which grade are uh, according to the grade only visible to check

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Easy one! giving brainly if correct​
Dafna1 [17]

Answer: glass is not considered as solute.

Extra's:

A solute is a substance that gets dissolved in a solvent. ... The solutes in air are oxygen, argon, and carbon dioxide gas, as well as water vapour.

Sugar is a solute in the solvent water. Sugar is one of the most soluble solutes in water.

Also solute is a powder that can be dissolved in solvent like water. here baking soda is a solute.

5 0
3 years ago
What do binary ionic compounds, binary molecular compounds, and binary acids have in common?
Fudgin [204]
Essentially the term binary, meaning each different thing has two components. Binary ionic compounds have two ionic compounds, binary molecular compounds have two molecular compounds, and binary acids have two acids.
8 0
3 years ago
Consider the reaction: 2 SO2(g)+O2(g)→2 SO3(g) If 285.5 mL of SO2 reacts with 158.9 mL of O2 (both measured at 315 K and 50.0 mm
Tanzania [10]

Answer:

a. Oxygen is the limiting reagent. n_{SO_3}^{Theoretical}=8.096x10^{-4}mol SO_3

b. Y=58.9%

Explanation:

Hello,

a. Limiting reagent and sulfur trioxide's theoretical yield.

At first, we must compute the involved moles for both sulfur dioxide's and oxygen's as follows, considering the volumes in liters and the pressure in atm of 50.0mmHg*1atm/760mmHg=0.0658atm:

n_{SO_2}=\frac{PV}{RT}=\frac{0.0658atm*0.2855L}{0.082\frac{atm*L}{mol*K}*315K} =7.273x10^{-3}molSO_2 \\n_{O_2}=\frac{PV}{RT}=\frac{0.0658atm*0.1589L}{0.082\frac{atm*L}{mol*K}*315K} =4.048x10^{-4}molO_2

Afterwards, by considering the properly balanced chemical reaction:

2SO_2(g)+O_2(g)-->2SO_3

We compute the oxygen's moles that completely reacts with the previously computed 7.273x10^{-3} moles of SO_2 as follows:

7.273x10^{-3}molSO_2*\frac{1molO_2}{2molSO_2} =3.6365x10^{-3}molO_2

That result let us know that the oxygen is the limiting reagent since just 4.048x10^{-4} moles are available in comparison with the 3.6365x10^{-3} moles that completely would react with 7.273x10^{-3} moles of SO_2.

Now, to compute the theoretical yield of sulfur trioxide, we apply the following stoichiometric relationship:

n_{SO_3}^{Theoretical}=4.048x10^{-4}molO_2*\frac{2molSO_3}{1molO_2} =8.096x10^{-4}mol SO_3

b. Percent yield.

At first, we must compute the collected (real) moles of sulfur trioxide:

n_{SO_3}^{real}=\frac{PV}{RT}=\frac{0.0658atm*0.1872L}{0.082\frac{atm*L}{mol*K}*315K} =4.769x10^{-4}molSO_3

Finally, we compute the percent yield:

Y=\frac{n_{SO_3}^{real}}{n_{SO_3}^{Theoretical}} *100%

Y=\frac{4.769x10^{-4}mol SO_3}{8.096x10^{-4}mol SO_3} *100%

Y=58.9%

Best regards.

7 0
3 years ago
Read 2 more answers
When calculating the average atomic mass, which of the following are needed for each isotope? Select all that apply.
Alexeev081 [22]

Answer:

number of protons, mass and atomic number

Explanation:

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3 years ago
At what points does the object accelrate please explain
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D to E

Is the answer that you're looking for

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