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natima [27]
3 years ago
12

Which is an anion ca2+ ag+ o2- k+

Chemistry
2 answers:
igor_vitrenko [27]3 years ago
8 0

Answer:

O2- is an anion

Explanation:

An atom or molecule is said to be neutral when it has a zero net charge. In contrast, if the system has a net charge it is termed as an ion.

A cation is an atom or a molecular system with a net positive charge whereas an anion carries a net negative charge.

In the given examples:

Ca2+ : net positive, cation

Ag+: net positive, cation

O2-: net negative, anion

K+: net positive, cation

a_sh-v [17]3 years ago
6 0
The 3rd one.
O2-
It is an Anion because the Oxygen atom has one extra electron from another atom.

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Calculate the molality (m) of solution containing 20.5 g of ethylene glycol C,H,O,
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How long does it take for a 12.62g sample of ammonia to heat from 209K to 367K if heated at a constant rate of 6.0kj/min? The me
Georgia [21]
First, consider the steps to heat the sample from 209 K to 367K.

1) Heating in liquid state from 209 K to 239.82 K

2) Vaporaizing at 239.82 K

3) Heating in gaseous state from 239.82 K to 367 K.


Second, calculate the amount of heat required for each step.

1) Liquid heating

Ammonia = NH3 => molar mass = 14.0 g/mol + 3*1g/mol = 17g/mol

=> number of moles = 12.62 g / 17 g/mol = 0.742 mol

Heat1 = #moles * heat capacity * ΔT

Heat1 = 0.742 mol * 80.8 J/mol*K * (239.82K - 209K) = 1,847.77 J

2) Vaporization

Heat2 = # moles * H vap

Heat2 = 0.742 mol * 23.33 kJ/mol = 17.31 kJ = 17310 J

3) Vapor heating

Heat3 = #moles * heat capacity * ΔT

Heat3 = 0.742 mol * 35.06 J / (mol*K) * (367K - 239.82K) = 3,308.53 J

Third, add up the heats for every steps:

Total heat = 1,847.77 J + 17,310 J + 3,308.53 J = 22,466.3 J

Fourth, divide the total heat by the heat rate:

Time = 22,466.3 J / (6000.0 J/min) = 3.7 min

Answer: 3.7 min


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3 years ago
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