If ƒ={(5, 1),(6, 2),(7, 3),(8, 1),(9, 7)}, then the range of ƒ is {(1, 5),(2, 6),(3, 7),(1, 8),(7, 9)} {1, 2, 3, 7} {5, 6, 7, 8,
navik [9.2K]
Answer:
{1,2,3,7}
Step-by-step explanation:
The range of a relation is the set of y-values of the ordered pairs.
The given relation is:
ƒ={(5, 1),(6, 2),(7, 3),(8, 1),(9, 7)},
The set of y-values of the given ordered pairs are;
{1,2,3,7}
Therefore the range of y is {1,2,3,7}
Answer:
No it is not a solution
Step-by-step explanation:
To solve this, you should replace your (x,y) with (8,3)- 8 being your x value and 3 being your y value.
So this inequality, your y value is supposed to be bigger than the value of whatever 3x-4 equals.
So, your inequality should be 3>3(8)-4
3*8=24-4=20
So is 3>(greater than)20? No. Which then means that (8,3) is not a solution because it would make the inequality not true.
Hope this helps!
Since you are subtracting 2 logs, you write the single log as a quotient.
Answer: B
Step-by-step explanation: You make the values in the parentheses equal to zero.
(X + 3) = 0
X = -3
A is wrong because the root would be 3, not negative 3. C is wrong because 3 isn’t guaranteed to be a root. D is wrong because -3 is a real solution.
Answer:
148
Step-by-step explanation:
