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saveliy_v [14]
1 year ago
6

• An object of mass 2.0 kg moves in uniform circular motion on a horizontal friction less table. The radius of the circle is 0.7

5 m and the centripetal force is 10.0 N. The work done by this force when the object moves through one-half of a complete revolution is​
Physics
1 answer:
Gekata [30.6K]1 year ago
4 0

Answer:

23.562

Explanation:

First it is good to work out the circumference:

2 pi r

2 pi .75

circumference = 4.7124

Next we need half of this because it is half a resolution. This will be our distance travelled.

half = 2.3562

word done = force x distance

work done = 10 x 2.3562

work done = 23.562

(I didn't see the need for mass...)

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pshichka [43]
Gs*rs^2 = gm*rm^2 
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7 0
4 years ago
Two students walk in the same direction along a straight path at a constant speed. One walks at a speed of 0.90 m/s and the othe
mr Goodwill [35]

Answer:

A. 456 seconds

Explanation:

We are given that two students walk in the same direction along a straight path at a constant speed.

One student walks with a speed=0.90 m/s

second student walks with speed=1.9 m/s

Total distance covered by each students=780 meter

We have to find who is faster and how much time  extra taken by slower student than the faster student.

Time taken by one student who travel with speed 0.90 m/s=\frac{780}{0.90}

Time=\frac{distance}{speed}

Time taken by one student who travel with speed 0.90 m/s

=\frac{780}{0.90}

Time taken by one student who travel with speed 0.90 m/s

=866.6 seconds

Time taken by second student who travel with speed 1.9 m/s=\frac{780}{1.9}

=410.5 seconds

The second student who travels with speed 1.9 m/s is faster than the student travels with speed 0.90 m/s .

Extra time taken by the student travels with speed 0.90 m/s=866.6-410.5=456.1 seconds

Extra time taken by the student travels with speed 0.90 m/s=456 seconds

Hence, option A is true.

7 0
3 years ago
Read 2 more answers
The relationship between sharks and remoras is characterized<br><br>TRUE <br>   OR<br>FALSE
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False, sharks and remoras have a symbiotic relationship. The remora removes parasites from the sharks scales, and the shark provides protection for the remora
8 0
3 years ago
A 26.2-kg dog is running northward at 3.02 m/s, while a 5.30-kg cat is running eastward at 2.74 m/s. Their 65.1-kg owner has the
REY [17]

Answer:

Angle with the +x axis is θ = 79.599degree

Then the velocity of owner = 1.235m/s

Explanation:

Given that the mass of dog is m1 =26.2 kg

velocity of dog is u1 = 3.02 m/s (north)

mass of cat is m2 = 5.3 kg

velocity is u2 = 2.74 m/s (east )

Mass of owner is M = 65.1 kg

Consider the east direction along +x axis andnorth along +y

momentum of dog is Py = m1 x u1

= 79.124 kg.m/s (j)

momentum of cat is Px = m2 x u2

= 14.522 kg.m/s (i)

Then the net magnitude of momentum is P = (Px2 + Py2)1/2

= 80.445

Angle with the +x axis is θ =tan-1(Py / Px ) = 79.599 degree

Then the velocity of owner is v = P / M = 1.235 m/s

3 0
3 years ago
Which is one-dimensional
Tema [17]

Answer:

B

Explanation:

They are all one-dimensional

6 0
3 years ago
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