Ask question

Ask question

All categories

1 month ago

6

• An object of mass 2.0 kg moves in uniform circular motion on a horizontal friction less table. The radius of the circle is 0.7

5 m and the centripetal force is 10.0 N. The work done by this force when the object moves through one-half of a complete revolution is

1 answer:

Gekata [30.6K]1 month ago

4 0

Answer:

23.562

Explanation:

First it is good to work out the circumference:

2 pi r

2 pi .75

circumference = 4.7124

Next we need half of this because it is half a resolution. This will be our distance travelled.

half = 2.3562

word done = force x distance

work done = 10 x 2.3562

work done = 23.562

(I didn't see the need for mass...)

You might be interested in

select the correct scientific notation form of this numeral 541 5 * 10^2 5.4 * 10^2 5.4 * 10^2 5.0 * 10^2

USPshnik [31]

To find the scientific notation, you need to divide at the decimal by the power of 10. So since there are 2 powers of 10, what you want to do is move the decimal 2 places to the left which will give you: .054

7 0

2 years ago

. One long wire carries a current of 30 A along the entire x axis. A second-long wire carries a current of 40 A perpendicular to

d1i1m1o1n [39]

Answer:

magnitude of net magnetic field at given point is

$B = 5 \times 10^{-6} T$

Explanation:

As we know that magnetic field due to a long current carrying wire is given as

$B = \frac{\mu_o i}{2\pi r}$

here we we will find the magnetic field due to wire which is along x axis is given as

$i = 30 A$

r = 2 m

now we have

$B_1 = \frac{4\pi \times 10^{-7} (30)}{2\pi (2m)}$

$B_1 = 3\times 10^{-6} T$ into the plane

Now similarly magnetic field due to another wire which is perpendicular to xy plane is given as

$i = 40 A$

r = 2 m

now we have

$B_2 = \frac{4\pi \times 10^{-7} (40)}{2\pi (2m)}$

$B_2 = 4\times 10^{-6} T$ along + x direction

Since the two magnetic field is perpendicular to each other

So here net magnetic field is given as

$B = \sqrt{B_1^2 + B_2^2}$

$B = 5 \times 10^{-6} T$

5 0

2 years ago

100 kw of power is delivered to the other side of a city by a pair of power lines with the voltage difference of 13014.1 v.

FinnZ [79.3K]

A) The power delivered to the lines is
$P_{in}= 100 kW=1 \cdot 10^5 W$
And the voltage at which the lines work is
$V=13014.1 V$
Since the power delivered is the product between the voltage and the current:
$P=VI$
We can find the current flowing in the lines:
$I= \frac{P}{V}= \frac{1 \cdot 10^5 W}{13014.1 V}=7.68 A$

b) The voltage change along each line can be found by using Ohm's law:
$\Delta V = IR = (7.68 A)(10 \Omega)=76.8 V$

c) The power wasted as heat along each line is given by:
$P_d = I^2 R = (7.68 A)^2 (10 \Omega) = 590 W$
And since we have 2 lines, the total power wasted as heat in both lines is
$P_d = 2 \cdot 590 W=1180 W$

6 0

2 years ago

When does the mechanical energy of a body falls freely equal twice its potential energy ?

Ilia_Sergeevich [38]

<span>As the body rises up its gravitational potential energy increases but its kinetic energy decreases.

As a body falls its gravitational potential energy decreases but it's kinetic energy increases</span>

4 0

2 years ago

A cryogenic vacuum pump works by condensing vapors onto some absorbent medium. This is an efficient and clean way to pump a syst

Julli [10]

Answer: Temperature in Fahrenheit is 577.4

Explanation:

The conversion factor for converting celcius to Fahrenheit is:

$F=\frac{9}{5}\times C+32$

where F = temperature in Fahrenheit

C = Temperature in Celcius

Given : Temperature difference in Celcius = $303^0C$

Putting in the values we get:

$F=\frac{9}{5}\times 303+32$

$F=577.4$

Thus the answer in Fahrenheit is 577.4

6 0

1 year ago