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3 years ago

14

How much heat is required to completely boil away 0.200 kg of water (ΔHv = 2.26 × 103 kJ/kg)?

2 answers:

alexandr1967 [171]3 years ago

4 0

We will use the formula:
Q = ml
where Q is the heat, m is the mass of substance, and l is the latent heat of vaporization of the substance.

Q = 0.2 x 2.26 x 10³
Q = 452 kJ

ratelena [41]3 years ago

3 0

<span>The heat required to completely boil away 0.200 kg of water is 4.52 × 102 kJ.
</span>

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