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3 years ago

How much heat is required to completely boil away 0.200 kg of water (ΔHv = 2.26 × 103 kJ/kg)?

2 answers:

alexandr1967 [171]3 years ago

4 0

We will use the formula:
Q = ml
where Q is the heat, m is the mass of substance, and l is the latent heat of vaporization of the substance.

Q = 0.2 x 2.26 x 10³
Q = 452 kJ

ratelena [41]3 years ago

3 0

<span>The heat required to completely boil away 0.200 kg of water is 4.52 × 102 kJ.
</span>

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Answer:

Sum of the forces will be equal to 3.479 N

Explanation:

We have given two same forces are oriented at an angle of 38°

Magnitude of each force is given $F_1=F_2=1.84$

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Sum of the forces will be equal to

$F=\sqrt{F_1^2+F_2^2+2F_1F_2cos\Theta }$

So sum of the forces will be equal to $F=\sqrt{1.84^2+1.84^2+2\times 1.84\times 1.84\times cos38^{\circ} }=3.479$

So sum of the force will be equal to 3.479 N

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Zad. 2 W marszobiegu chłopiec przebiegł 900 m w ciągu 205 min, a następnie przeszedł 300m w tym danym czasie. Jaka była średnia

USPshnik [31]

Odpowiedź:

0,049 m / s

Wyjaśnienie:

Biorąc pod uwagę, że:

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Hi Pupil Here's Your answer :::

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The pressure of a gas is reduced from 1200.0 mm hg to 850.0 mm hg as the volume of its container is increased by moving a piston

Kamila [148]

From gas laws:
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