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son4ous [18]
3 years ago
14

Which is one-dimensional

Physics
1 answer:
Tema [17]3 years ago
6 0

Answer:

B

Explanation:

They are all one-dimensional

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A planet outside of our solar system
Zolol [24]

Answer:

exoplanets is any planet beyond our solar system.

4 0
3 years ago
3. How much work is done when you pull a 6 N wagon for 5 meters?
8090 [49]

Answer:

<h2>30 J</h2>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question

force = 6 N

distance = 5 m

We have

workdone = 6 × 5 = 30

We have the final answer as

<h3>30 J</h3>

Hope this helps you

3 0
3 years ago
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eimsori [14]
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8 0
3 years ago
Metabolic power is the rate at which your body "burns" fuel to power your activities. For many activities, your body is roughly
DerKrebs [107]

Answer:

Metabolic power 420.138 W

Explanation:

Given data:

considering drag coefficient Cd =  0.9

Assuming cross section of cyclist A = 0.50 m^2

Take density of air ρ = 1.2 kg/m3

We know that drag force is given as

Drag\ Force = Cd\times 1/2 \times \rho AV^2&#10;

D = 0.9\times 1/2\times 1.2\times 0.5\times 7.3^2&#10;

D = 14.388 N

Power = D\times V = 14.388\times 7.3 = 105.03 W

hence metabolic power is given as

Metabolic power = \frac{D}{\eta}

                   = \frac{105.03}{0.25}

                          = 420.138 W

7 0
3 years ago
Calculate the specific heat capacity of a piece of wood if 150.0g of the wood absorbs 67,000 joules of heat, and it’s temperatur
svet-max [94.6K]

Answer:

17.8 J/g^{\circ}C

Explanation:

When a certain amount of substance is supplied with a certain amount of energy Q, the temperature of the substance increases according to the equation

Q=mC\Delta T

where

m is the mass of the substance

C is the specific heat capacity

\Delta T is the change in temperature

In this problem:

m = 150.0 g is the mass of wood

Q=67,000 J is the amount of energy supplied to the wood

\Delta T=55-30=25^{\circ}C is the increase in temperature of the substance

Therefore, the specific heat capacity is:

C=\frac{Q}{m\Delta T}=\frac{67,000}{(150.0)(25)}=17.8 J/g^{\circ}C

5 0
3 years ago
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