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Elanso [62]
3 years ago
5

Two students walk in the same direction along a straight path at a constant speed. One walks at a speed of 0.90 m/s and the othe

r at a speed of 1.9 m/s. Assuming they have started at the same point at the same time, how much sooner does the faster student arrive at the destination 780 miles away?
A) 456 seconds
B) 411 seconds
C) 780 seconds
D) 867 seconds
Physics
2 answers:
mr Goodwill [35]3 years ago
7 0

Answer:

A. 456 seconds

Explanation:

We are given that two students walk in the same direction along a straight path at a constant speed.

One student walks with a speed=0.90 m/s

second student walks with speed=1.9 m/s

Total distance covered by each students=780 meter

We have to find who is faster and how much time  extra taken by slower student than the faster student.

Time taken by one student who travel with speed 0.90 m/s=\frac{780}{0.90}

Time=\frac{distance}{speed}

Time taken by one student who travel with speed 0.90 m/s

=\frac{780}{0.90}

Time taken by one student who travel with speed 0.90 m/s

=866.6 seconds

Time taken by second student who travel with speed 1.9 m/s=\frac{780}{1.9}

=410.5 seconds

The second student who travels with speed 1.9 m/s is faster than the student travels with speed 0.90 m/s .

Extra time taken by the student travels with speed 0.90 m/s=866.6-410.5=456.1 seconds

Extra time taken by the student travels with speed 0.90 m/s=456 seconds

Hence, option A is true.

katovenus [111]3 years ago
3 0
<h3>The correct answer is A) 456 seconds.</h3><h3>Further Explanation</h3>

Speed is how far something travels per unit time. It is determined from the ratio of the distance covered and the time it took to cover such distance. It can be represented symbolically using the equation below:

speed = \frac{distance}{time}

To solve the problem, first sort the given:

distance traveled = 780 m

(<em>NOTE:</em> <em>the destination is 780 meters from the origin not 780 miles away. None of the options will be viable if the distance was in miles.)</em>

speed of student 1 = 0..90 m/s

speed of student 2 = 1.9 m/s

The question is asking to find the difference in the time of arrival of student 1 and student 2. To do this, the following steps must be done:

  1. Calculate the time it will take for each student to arrive 780 m away from their origin.
  2. Get the difference in the time.

<u>STEP 1:</u> Use the speed to calculate the time taken to travel a distance of 780 meters. The general equation to be used is:

time = \frac{distance}{speed}

<em>For Student 1:</em>

time = \frac{780 \ m}{0.90 \frac{m}{s}}\\\boxed {time = 866.67 \ s}

<em>For Student 2:</em>

<em>time = \frac{780 \ m}{1.9 \frac{m}{s}}\\\boxed {time = 410.53 \ s}</em>

<u>STEP 2:</u> To determine how sooner the faster student reaches the destination, get the difference between their times.

866.67 \ s \ - 410.53 \ s \ = \boxed {\boxed {\ 456.14 \ s}}

The difference in time shows how many seconds elapse before the slower student arrives.

Rounding off the answer to the nearest whole number gives the correct answer which is A) 456 seconds.

<h3>Learn More</h3>
  1. Learn more about velocity brainly.com/question/862972
  2. Learn more about distance - time graphs brainly.com/question/1378025
  3. Learn more about distance brainly.com/question/12971902

<em>Keywords: speed, distance, time</em>

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The terminal velocity of gold sphere is 39.2 cm/s

<h3>What is terminal velocity?</h3>

Terminal velocity is the maximum velocity attainable for an object as it falls through a fluid.

<h3>How to calculate the terminal velocity of the gold sphere?</h3>

The terminal velocity of the gold sphere is given by v = 2gr²(ρ - σ)/9η where

  • g = acceleration due to gravity = 9.8 m/s²,
  • r = radius of sphere = 100 μm = 100 × 10⁻⁶ m = 10⁻⁴ m = 10⁻² cm,
  • ρ = density of sphere = 19 g/cm³,
  • σ = density of water = 1.0 g/cm³ and
  • η = viscosity of water = 10⁻³ Pa-s

So, susbtituting the values of the variables into the equation, we have that

v = 2gr²(ρ - σ)/9η

v = 2 × 9.8m/s²× (10⁻² cm)²(19 g/cm³ - 1.0 g/cm³)/(9 × 10⁻³ Pa-s)

v = 2 × 9.8 m/s² × 10⁻⁴ cm² × (18 g/cm³)/(9 × 10⁻³ Pa-s)

v = 2 × 980 cm/s² × 10⁻⁴ cm² × 2 g/cm³/(1 × 10⁻³ Pa-s)

v = 3920 g/s² × 10⁻⁴/(1 × 10⁻³ Pa-s)

v = 392 cm/s × 10³ × 10⁻⁴

v = 392 × 10⁻¹ cm/s

v = 39.2 cm/s

So, the terminal velocity is 39.2 cm/s

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4 0
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A vessel that contains a gas has two pressure gauges attached to it. One contains liquid mercury, and the other an oil such as d
castortr0y [4]

Answer:

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Explanation:

First, we can use the following sketch for an easy understanding, in the attached image we can see the two pressure gauges the one with mercury to the right and the other one with oil to left. We have all the information needed in the mercury pressure gauge, so we can determine the pressure inside the vessel because the fluid is a gas it will have the same pressure distributed inside the vessel (P1).

Since P1 = Pgas, we can use the same formula, but this time we need to determine the height of the column of oil in the pressure gauge.

The result is that the height of the oil column is higher than the height of the one that uses mercury, this is due to the higher density of mercury compared to oil.

Note: the information given in the units of the fluids is not correct because the density is always expressed in units of (mass /volume)

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The orbits of ____ lie closer to the sun than does earth's orbit.
Eva8 [605]

Answer:

Mercury and Venus lie closer to Sun than position of Earth

Explanation:

As we know that all planets around the sun in the range of their distance can be arranged as following:

1). Mercury.

2). Venus.

3). Earth.

4). Mars.

5). Jupiter.

6). Saturn.

7). Uranus.

8). Neptune.

Since Earth lie at 3rd position from sun so two closer planets are Mercury and Venus

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Which word in the following sentence should be capitalized in order to follow the conventions of Standard English?
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3 years ago
A physical pendulum consists of a meter stick that is pivoted at a small hole drilled through the stick a distance d from the 50
PSYCHO15rus [73]

Answer:

(a). The value of d is 0.056 cm and 1.496 cm.

(b). The time period is 1.35 sec.

Explanation:

Given that,

Length = 50.00 cm

Time period = 2.50 s

Time period of pendulum is defined as the time for one complete cycle.

The period depends on the length of the pendulum.

Using formula of time period

T=2\pi\sqrt{\dfrac{I}{mgh}}

Where, I = moment of inertia

We need to calculate the value of d

Using parallel theorem of moment of inertia

I=I_{cm}+md^2

For a meter stick mass m , the rotational inertia about it's center of mass

I_{cm}-\dfrac{mL^2}{12}

Where, L = 1 m

Put the value into the formula of time period

T=2\pi\sqrt{\dfrac{\dfrac{mL^2}{12}+md^2}{mgd}}

T=2\pi\sqrt{\dfrac{L^2}{12gd}+\dfrac{d}{g}}

T^2=4\pi^2(\dfrac{L^2}{12gd}+\dfrac{d}{g})

Multiplying both sides by d

tex]T^2d=4\pi^2(\dfrac{L^2}{12g}+\dfrac{d^2}{g})[/tex]

(\dfrac{4\pi^2}{g})d^2-T^2d+\dfrac{\pi^2L^2}{3g}=0

Put the value of T, L and g into the formula

4.028d^2-6.25d+0.336=0

d = 0.056\ m, 1.496\ m

The value of d is 0.056 cm and 1.496 cm.

(b). Given that,

L = 50-5 = 45 cm

We need to calculate the time period

Using formula of period

T=2\pi\sqrt{\dfrac{l}{g}}

Put the value into the formula

T=2\pi\sqrt{\dfrac{45\times10^{-2}}{9.8}}

T=1.35\ sec

Hence, (a). The value of d is 0.056 cm and 1.496 cm.

(b). The time period is 1.35 sec.

7 0
3 years ago
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