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Vadim26 [7]
3 years ago
13

What changes happens when you run ?

Chemistry
2 answers:
tekilochka [14]3 years ago
6 0

Answer:

more detail please

Explanation:

Tju [1.3M]3 years ago
5 0
More detail needed for an answer
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Which of the following latitudes receive the most direct solar energy?
Misha Larkins [42]

Answer:

The answer to your question is D.

Explanation:

The latitudes near the equator receives the most direct solar energy.

Hope this helps :)

8 0
3 years ago
HELP ASAP!! PLEASE !!
ZanzabumX [31]

Answer:

8,3, 7,7

Explanation:

6 0
3 years ago
Th e molar absorption coeffi cient of a substance dissolved in water is known to be 855 dm3 mol−1 cm−1 at 270 nm. To determine t
Olegator [25]

Answer : The percentage reduction in intensity is 79.80 %

Explanation :

Using Beer-Lambert's law :

A=\epsilon \times C\times l

A=\log \frac{I_o}{I}

\log \frac{I_o}{I}=\epsilon \times C\times l

where,

A = absorbance of solution

C = concentration of solution = 3.25mmol.dm^{3-}=3.25\times 10^{-3}mol.dm^{-3}

l = path length = 2.5 mm = 0.25 cm

I_o = incident light

I = transmitted light

\epsilon = molar absorptivity coefficient = 855dm^3mol^{-1}cm^{-1}

Now put all the given values in the above formula, we get:

\log \frac{I_o}{I}=(855dm^3mol^{-1}cm^{-1})\times (3.25\times 10^{-3}mol.dm^{-3})\times (0.25cm)

\log \frac{I_o}{I}=0.6947

\frac{I_o}{I}=10^{0.6947}=4.951

If we consider I_o = 100

then, I=\frac{100}{4.951}=20.198

Here 'I' intensity of transmitted light = 20.198

Thus, the intensity of absorbed light I_A = 100 - 20.198 = 79.80

Now we have to calculate the percentage reduction in intensity.

\% \text{reduction in intensity}=\frac{I_A}{I_o}\times 100

\% \text{reduction in intensity}=\frac{79.80}{100}\times 100=79.80\%

Therefore, the percentage reduction in intensity is 79.80 %

3 0
4 years ago
A gas occupies 2.0 m3 at 100.0k and exerts a pressure of 100.0kPa. What volume will the gas occupy if the temperature is increas
Svetradugi [14.3K]
According to ideal gas equation, we know for 1 mole of gas: PV=RT
where P = pressure,  T = temperature, R = gas constant, V= volume
If '1' and '2' indicates initial and final experimental conditions, we have
\frac{P1V1}{P2V2} =  \frac{T1}{T2}

Given that: V1 = 100.0 kPa, T1 = 100.0 K, V1 = 2.0 m3, T2 = 400 K, P2 = 200.0 kPa

∴ on rearranging above eq., we get V2 = \frac{P1V1T2}{T1} =  \frac{100 X 2 X 400}{200X100}
∴ V2 = 4 m3 
7 0
3 years ago
The pH of a solution is 2.0. Which statement is correct? Useful formulas include , , , and .
allsm [11]

Answer:

if the pH of a solution is 2.0 that means the solution would be acidic.

Explanation:

3 0
3 years ago
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