The answer is around 4.12x10^23 molecules
Answer:
Phase transition is when a substance changes from a solid, liquid, or gas state to a different state. Every element and substance can transition from one phase to another at a specific combination of temperature and pressure.
Explanation:
Answer:
<h3>A) a chemical change started immediately and finished at 8 minutes!!</h3>
Explanation:
it is stated that the substance <em>slowly </em>starts turning blue, not that it suddenly started changing!! and, this couldn't be a non-chemical change because there are very few chemicals that can turn a completely different color when the two substances were the same color!!! ^_^ please let me know if messed anything up
Click the image above... Er, The blank white space above.
(it looks white in the preview, but that's because the bottom half of the image is blank)
. H - C triple bond C - H.
The balanced half-reaction for the product that forms at anode is Fe⁺² + 2e⁻ → Fe(s) and 2H₂O + 2e⁻ → H₂ + 2OH⁻, the product that forms at cathode is 2I⁻ → I₂ + 2e- and 2H₂O → O₂ + 4H⁺ + 4e⁻
<h3>What is Balanced Chemical Equation ?</h3>
The equation during which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation is called balanced chemical equation.
Now write the equation for FeI₂
At cathode:
Fe⁺² + 2e⁻ → Fe(s) Eo = - 0.44 V
2H₂O + 2e⁻ → H₂ + 2OH⁻ Eo = - 0.827 V
It is easy to decrease Fe⁺² ions than the water, the product which is formed at cathode is Iron.
At anode:
2I⁻ → I₂ + 2e- Eo = - 0.54 V
2H₂O → O₂ + 4H⁺ + 4e⁻ Eo = -1.23 V
O₂ gas formed at anode.
Thus from the above conclusion we can say that The balanced half-reaction for the product at anode is Fe⁺² + 2e⁻ → Fe(s) and 2H₂O + 2e⁻ → H₂ + 2OH⁻, the product that forms at cathode is 2I⁻ → I₂ + 2e- and 2H₂O → O₂ + 4H⁺ + 4e⁻.
Learn more about the Balanced chemical equation here: brainly.com/question/26694427
#SPJ4