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1 year ago

9.

Chemistry

1 answer:

mart [117]1 year ago

8 0

An example of an intensive property of matter is the density of water is 1000 kg/m3. The correct option is C.

<h3>What are intensive properties?</h3>

Intensive properties are those properties that do not depend upon the amount of substance. These properties are density, color, chemical potential, reactivity, etc.

There are two types of properties on the basis of physical quality. They are intensive and expensive. Intensive properties do not depend upon the size and abstraction of the substance.

Thus, the correct option is C. The density of water is 1000 kg/m3.

To learn more about intensive properties, refer to the link:

brainly.com/question/13733851

#SPJ1

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What are the resonance structures of the<br>carbonate (CO32-) ion?

postnew [5]

Answer:

go search google so dum

Explanation:

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3 years ago

(b) what is the major product of the reaction at very low temperatures?

svlad2 [7]

The reaction is low b/c of the tempature. that's why.

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3 years ago

A chemistry teacher adds 50.0 mL of 1.50 M H2SO4 solution to 200 mL of water. What is the concentration of the final solution? A

anygoal [31]

this is a dilution equation where 50.0 mL of 1.50 M H₂SO₄ is taken and added to 200 mL of water.

c1v1 = c2v2

where c1 is concentration and v1 is volume of the concentrated solution

and c2 is concentration and v2 is volume of the diluted solution to be prepared

50.0 mL of 1.50 M H₂SO₄ is added to 200 mL of water so the final solution volume is - 200 + 50.0 = 250 mL

substituting these values in the formula

1.50 M x 50.0 mL = C x 250 mL

C = 0.300 M

concentration of the final solution is A) 0.300 M

4 0

3 years ago

Read 2 more answers

Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch

mamaluj [8]

Answer:

Explanation:

From the given information:

The equation for the reaction can be represented as:

$2SO_2 + O_2 \to 2SO_3$

The I.C.E table can be represented as:

2SO₂ O₂ 2SO₃

Initial: 14 2.6 0

Change: -2x -x +2x

Equilibrium: 14 - 2x 2.6 - x 2x

However, Since the amount of sulfur trioxide gas to be 1.6 mol.

SO₃ = 2x,

then x = 1.6/2

x = 0.8 mol

For 2SO₂; we have 14 - 2x

= 14 - 2(0.8)

= 14 - 1.6

= 12.4 mol

For O₂; we have 2.6 - x

= 2.6 - 1.6

= 1.0 mol

Thus;

[SO₂] = moles / volume = ( 12.4/50) = 0.248 M ,

[O₂] = 1/50 = 0.02 M ,

[SO₃] = 1.6/50 = 0.032 M

Kc = [SO₃]² / [SO₂]² [O₂]

= ( 0.032²) / ( 0.248² x 0.02)

= 0.8325

Recall that; the equilibrium constant for the reaction $2SO_2 + O_2 \to 2SO_3$ = 0.8325;

If we want to find:

$SO_2 + \dfrac{1}{2}O_2 \to SO_3$

Then:

$K_c = (0.8325)^{1/2}$

$\mathbf{K_c = 0.912}$

Since no temperature is given to use in the question, it will be impossible to find the final temperature of the mixture.

7 0

3 years ago

PLEASE HELP I DONT WANT TO FAIL!! ):

Fudgin [204]

Hope this helps :) I didn’t know how to write subscripts so I wrote it down on some paper.

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3 years ago