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1 year ago

9.

Chemistry

1 answer:

mart [117]1 year ago

8 0

An example of an intensive property of matter is the density of water is 1000 kg/m3. The correct option is C.

<h3>What are intensive properties?</h3>

Intensive properties are those properties that do not depend upon the amount of substance. These properties are density, color, chemical potential, reactivity, etc.

There are two types of properties on the basis of physical quality. They are intensive and expensive. Intensive properties do not depend upon the size and abstraction of the substance.

Thus, the correct option is C. The density of water is 1000 kg/m3.

To learn more about intensive properties, refer to the link:

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Chromic acid (H2CrO4) is an acid that is used in ceramic glazes and colored glass. The pH of a 0.078 M solution of chromic acid

cestrela7 [59]

Answer:

Ka = 0.1815

Explanation:

Chromic acid

pH = ?

Concentration = 0.078 M

Ka = ?

HCl

conc. = 0.059M

pH = -log(H+)

pH = -log(0.059) = 1.23

pH of chromic acid = 1.23

Step 1 - Set up Initial, Change, Equilibrium table;

H2CrO4 ⇄ H+ + HCrO4−

Initial - 0.078M 0 0

Change : -x +x +x

Equilibrium : 0.078-x x x

Step 2- Write Ka as Ratio of Conjugate Base to Acid

The dissociation constant Ka is [H+] [HCrO4−] / [H2CrO4].

Step 3 - Plug in Values from the Table

Ka = x * x / 0.078-x

Step 4 - Note that x is Related to pH and Calculate Ka

[H+] = 10^-pH.

Since x = [H+] and you know the pH of the solution,

you can write x = 10^-1.23.

It is now possible to find a numerical value for Ka.

Ka = (10^-1.23))^2 / (0.078 - 10^-1.23) = 0.00347 / 0.0191156

Ka = 0.1815

4 0

3 years ago

How can we increase the rate of collisions between the reactants in this reaction? mg 2hcl → mgcl2 h2

Minchanka [31]

<u>The frequency of </u><u>collisions </u><u>between the two reactants increases as the </u><u>concentration </u><u>of the reactants increases</u>. When collisions happen, they don't always cause a reaction (atoms misaligned or insufficient energy, etc.). Higher concentrations result in more collisions and reaction opportunities.

Increasing a reactant's surface area increases the frequency of collisions and thus the reaction rate. The surface area of several smaller particles is greater than that of a single large particle. The greater the available surface area for particles to collide, the faster the reaction will occur.

<h3>How does concentration affect the rate of collisions between reactants?</h3>

Thus, we can conclude that by increasing the concentration of Mg in the reaction mixture we increase the rate of collisions between the reactants in this reaction.

<h3>What does the half reaction of an oxidation-reduction reaction show?</h3>

Iron gains electrons in the half reaction of an oxidation-reduction reaction. What does iron's electron gain mean? It has been reduced. Predict the product that will precipitate out of the reaction using the solubility rules and the periodic table.

Learn more about collisions of particles:

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4 0

2 years ago

What changes could be made to optimize the manufacturing process

Blizzard [7]

Manufacturers can generate new value minimize cost and increase operational stability by focusing on 4 broad areas management Supply Circle product design and value recovery

7 0

3 years ago

Calculate the change in the entropy of the system and also the change in the entropy of the surroundings, and the resulting tota

Ghella [55]

Answer:

(a) Δ $S_{sys}$ = 2.881 J/K; Δ $S_{sur}$ = -2.881 J/K; total change in entropy = 0

(b)Δ $S_{sys}$ = 2.881 J/K; Δ $S_{sur}$ = 0 ; total change in entropy = 2.881 J/K

Explanation:

In the given problem, we need to calculate the change in the entropy of the system and also the change in the entropy of the surroundings, and the resulting total change in entropy, when a sample of nitrogen gas of mass 14 g at 298 K and 1.00 bar doubles its volume. We have the following variable:

mass (m) = 14 g

Temperature = 298 K

Pressure = 1.00 bar

Initial volume = $V_{1}$