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Gnesinka [82]
1 year ago
9

Did you ever purchase a bag of M & M Peanut candies and wonder about the distribution of the colors ? A recent article repor

ted that 30 percent of the candies are brown , 20 percent yellow , 20 percent red , 20 percent green , and 10 percent orange . A one - pound bag of M & M peanut candies was purchased at Wal - Mart here in Lubbock . A total of 188 candies were in the bag , with 67 brown , 22 yellow , 51 red , 24 green , and 24 orange .
Mathematics
1 answer:
Vika [28.1K]1 year ago
3 0

Filling in the frequency table according to the colors observed and expected on the M & M Peanut candies is as follows:

<h3>Frequency Table:</h3>

Color                              Brown    Yellow     Red      Green     Orange    Total

<h3>Absolute Frequencies</h3>

Observed Frequency     67           22           51           24           24         188

Expected Frequency     56           38           38           38            18         188    

<h3>Relative Frequencies:</h3>

Observed Frequency   36%         12%       27%         13%          13%

Expected Frequency    30%        20%      20%        20%          10%

<h3>What is a frequency table?</h3>

A frequency table is a display of the number of occurrences of a particular value or characteristic.

A frequency table makes it easy to display and interpret a distribution of data.

The absolute frequencies shows the absolute values of the observed and expected frequencies, while the relative frequencies shows the percentage values of the observed and expected frequencies.

<h3>Data and Calculations:</h3>

Color                              Brown    Yellow     Red      Green     Orange    Total

Observed Frequency     67           22           51           24           24         188

Expected Frequency     30%        20%       20%        20%         10%      100%

Learn more about frequency tables at brainly.com/question/1094036

#SPJ1

<h3>Question Completion:</h3>

Fill in the following table on the frequency of the colors, indicating the absolute and relative frequencies of the distributions.

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Answer:

Absolute minimum = 1.414

Absolute maximum = 2.828

Step-by-step explanation:

g(x,y)=\sqrt {x^2+y^2} \ constraints: 1\leq x\leq 2 ,\ 1\leq y\leq2

For absolute minimum we take the minimum values of x and y.

x_{minimum} =1\\y_{minimum}=1\\

Plugging in the minimum values in the function.

g(1,1)=\sqrt {1^2+1^2}\\g(1,1) = \sqrt{1+1}\\g(1,1)=\sqrt {2}\\g(1,1)=\pm 1.414\\

Absolute minimum value will be always positive.

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For absolute maximum we take the maximum values of x and y.

x_{maximum} =2\\y_{maximum}=2\\

Plugging in the maximum values in the function.

g(2,2)=\sqrt {2^2+2^2}\\g(2,2) = \sqrt{4+4}\\g(2,2)=\sqrt {8}\\g(2,2)=\pm 2.828\\

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Answer:

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Mass of;

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salt = 120g

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mass of mixture = sum of its components

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