How many atoms are present in 179.0 g of iridium?

Please help me please

Brut [27]

I am only in 6th grade so all I have to say is good luck and I wish you the best on that quiz.

6 0

3 years ago

Which reaction is capable of breaking polypeptides into their component amino acids?

Bad White [126]

Answer: B. Hydrolysis (adding water)

Explanation:

When peptide bonds join two or more amino acids together, this is refered to as a peptide. A polypeptide simply means several amino acids. We should also note that proteins contains polypeptides.

The reaction that is capable of breaking polypeptides into their component amino acids is hydrolysis. This simply means a chemical process whereby a water molecule is being added to a particular substance.

4 0

3 years ago

A substance X contains 10 gram of calcium carbonate calculate the number of mole of calcium carbonate present in X

Tasya [4]

$\LARGE{ \boxed{ \rm{ \red{Required \: answer}}}}$

☃️ Chemical formulae ➝ $\sf{CaCO_3}$

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

$\boxed{ \sf{No. \: of \: moles = \frac{given \: weight}{molecular \: weight} }}$

<h3><u>Solution:</u></h3>

Atomic weight of elements:

Ca = 40

C = 12

O = 16

❍ Molecular weight of $\sf{CaCO_3}$

= 40 + 12 + 3 × 16

= 52 + 48

= 100 g/mol

❍ Given weight: 10 g

Then, no. of moles,

⇛ No. of moles = 10 g / 100 g mol‐¹

⇛ No. of moles = 0.1 moles

☄ No. of moles of Calcium carbonate in that substance = <u>0.1 moles</u>

<u>━━━━━━━━━━━━━━━━━━━━</u>

3 0

4 years ago

Read 2 more answers

Determine the empirical formula for compounds that have the following analyses: a. 66.0% barium and 34.0% chlorine b. 80.38% bis

almond37 [142]

Answer: a) $BaCl_2$

b) $BiO_3H_3$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

a) Mass of Ba= 66.06 g

Mass of Cl = 34.0 g

Step 1 : convert given masses into moles.

Moles of Ba = $\frac{\text{ given mass of ba}}{\text{ molar mass of Ba}}= \frac{66.06g}{137g/mole}=0.48moles$

Moles of Cl = \frac{\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac{34g}{35.5g/mole}=0.96moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Ba = $\frac{0.48}{0.48}=1$

For O = $\frac{0.96}{0.48}=2$

The ratio of Ba: Cl= 1:2

Hence the empirical formula is $BaCl_2$

b) Mass of Bi= 80.38 g

Mass of O= 18.46 g

Mass of H = 1.16 g

Step 1 : convert given masses into moles.

Moles of Bi = $\frac{\text{ given mass of ba}}{\text{ molar mass of Ba}}= \frac{80.38g}{209g/mole}=0.38moles$

Moles of O= $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{18.46g}{16g/mole}=1.15moles$

Moles of H= $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{1.16g}{1g/mole}=1.16moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Bi= $\frac{0.38}{0.38}=1$

For O = $\frac{1.15}{0.38}=3$

For H= $\frac{1.16}{0.38}=3$

The ratio of Bi: O: H= 1:3: 3

Hence the empirical formula is $BiO_3H_3$

6 0

3 years ago

Which of the following is a possible Noble gas notation? [Xe] 6s26p6 [Kr] 5s25d85p6 [Xe] 6s25d106p4 [Kr] 5s24d105p6

Mice21 [21]

Answer is: [Kr] 5s24d105p6.

1) [Xe] 6s²6p⁶ is not correct, because element with atomic number 62 (54 + 8) is samarium with electron configuration [Xe] 6s²4f⁶.

Xenon (Xe) is noble gas with atomic number 54, which means it has 54 protons and 54 electrons.

Electron configuration of xenon atom:

₅₄Xe 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁶.

2) [Kr] 5s²5d⁸5p⁶ is not correct, because element with atomic number 52 (36 + 16) is tellurium.

Tellurium (Te) is an element with atomic number 52 (52 protons and 52 electrons), it is in group 16 (chalcogens) and period 5 (principal quantum number n = 5, which means it has 5 electrons shell) of Periodic table.

Electron configuration of tellurium atom:

₅₂Te 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 4d¹⁰ 5s² 5p⁴ or [Kr] 4d¹⁰5s²5p⁶.

Krypton is a chemical element with symbol Kr and atomic number 36, which means it has 36 protons and 36 electrons.

Electron configuration of krypton atom:

₃₆Kr 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶.

3) [Xe] 6s²5d¹⁰6p⁴ is not correct, because element with atomic number 70 (54 + 16) is ytterbium (Yb) with electron configuration [Xe] 6s²4f¹⁴.

4) [Kr] 5s²4d¹⁰5p⁶ is correct, because element with atomic number 54 (36 + 18) is krypton (Kr) with electron configuration 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ or [Kr] 5s²4d¹⁰5p⁶.

7 0

3 years ago

Read 2 more answers