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ludmilkaskok [199]
3 years ago
6

**ASAP**

Chemistry
2 answers:
jek_recluse [69]3 years ago
4 0

the answer is C) . I hope this was helpful!

9966 [12]3 years ago
3 0

Answer:

c.) the smallest mass of material that can sustain a chain reaction

Explanation:

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Answer:

D

Explanation:

Scientists always perform tests and observe and measure in the physical world to prove their points or answer their questions.

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What is the next atomic orbital in the series 1s 2p 3s 3p
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s an example, the ground state configuration of the sodium atom is 1s22s22p63s1, as deduced from the Aufbau principle (see below). The first excited state is obtained by promoting a 3s electron to the 3p orbital, to obtain the 1s22s22p63p1 configuration, abbreviated as the 3p level.

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An earthquake causes a one 100 mile square area to be fractured into four different geographical areas. Two of the areas have a
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Use the data given below to construct a Born-Haber cycle to determine the heat of formation of KCl. Δ H°(kJ) K(s) → K(g) 89 K(g)
AURORKA [14]

Explanation:

The net equation will be as follows.

          K(s) + Cl_{2}(g) \rightarrow KCl(s)

So, we are required to find \Delta H_{formation} for this reaction.

Therefore, steps involved for the above process are as follows.

Step 1:  Convert K from solid state to gaseous state

          K(s) \rightarrow K(g),    \Delta H_{1} = 89 kJ

Step 2:  Ionization of gaseous K

           K(g) \rightarrow K^{+}(g) + e^{-},    H_{2} = 418 KJ

Step 3:  Dissociation of Cl_{2} gas into chlorine atom .

            \frac{1}{2} Cl_{2}(g) \rightarrow Cl(g),   \Delta H_{3} = \frac{244}{2} = 122 KJ

Step 4: Iozination of chlorine atom.

              Cl(g) + e^{-} \rightarro Cl^{-}(g),      H_{4} = -349 KJ

Step 5:  Add K^{+} ion and Cl^{-} ion formed above to get KCl .

              K^{+}(g) + Cl^{-}(g) \rightarrow KCl(s),   H_{5} = -717 KJ

Now, using Born-Haber cycle, value of enthalpy of the formation is calculated as follows.

      \Delta H_{f} = \DeltaH_{1} + \Delta H_{2} + \Delta H_{3} + \Delta H_{4} + \Delta H_{5}

                  = 89 + 418 + 122 - 349 - 717

                  = - 437 KJ/mol

Thus, we can conclude that the heat of formation of KCl is - 437 KJ/mol.

5 0
3 years ago
Need help please?!!!!!​
puteri [66]

(a) 33.6 L of oxygen would be produced.

(b) 106 grams of  Na_2CO_3 would be needed

<h3>Stoichiometric calculations</h3>

1 mole of gas = 22.4 L

(a) From the equation, 2 moles of KClO_3 produce 3 moles of O_2. 1 mole of  KClO_3 will, therefore, produce 1.5 moles of  O_2.

1.5 moles of oxygen = 22.4 x 1.5 = 33.6 L

(b) 22.4 L of CO_2 is produced at STP. This means that 1 mole of the gas is produced.

From the equation, 1 mole of  CO_2 requires 1 mole of Na_2CO_3.

Molar mass of  Na_2CO_3 = (23x2)+ (12)+(16x3) = 106 g/mol

Mass of 1 mole  Na_2CO_3 = 1 x 106 = 106 grams

More on stoichiometric calculations can be found here: brainly.com/question/27287858

#SPJ1

6 0
2 years ago
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