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tigry1 [53]
3 years ago
14

How many aluminium atoms are there in the formula for aluminium nitrate ?

Chemistry
1 answer:
telo118 [61]3 years ago
8 0
The formula for Aluminium Nitrate is Al(NO _{3} )_{3}.

This is because aluminium has a 3+ charge and nitrate has a 1- charge, so you need 3 of them to balance out aluminium.

Therefore, you have one ion of aluminium.
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aleksandrvk [35]
2.a)R b)R c)L d)L e)R f)L g)L
8 0
3 years ago
What does Gibbs free energy predict?
7nadin3 [17]

Answer:

D. It predicts whether or not a reaction will be spontaneous.

Explanation:

<em>What does Gibbs free energy (ΔG) predict? .</em>

A. It predicts what the rate of the reaction will be. NO. ΔG is a thermodynamical parameter and it is not related to the kinetics of the reaction.

B. It predicts how high the activation energy is. NO. ΔG is a thermodynamical parameter and it is not related to the kinetics of the reaction.

C. It predicts if entropy will increase or decrease. NO. ΔG depends on the entropy but not the other way around.

D. It predicts whether or not a reaction will be spontaneous. YES. If ΔG < 0 the reaction is spontaneous and if ΔG > 0 the reaction is not spontaneous.

5 0
3 years ago
The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in diethyl et
Alexxx [7]

<u>Answer:</u> The vapor pressure of solution is 459.17 mmHg

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For testosterone:</u>

Given mass of testosterone = 7.752 g

Molar mass of testosterone = 288.4 g/mol

Putting values in equation 1, we get:

\text{Moles of testosterone}=\frac{7.752g}{288.4g/mol}=0.027mol

  • <u>For diethyl ether:</u>

Given mass of diethyl ether = 208.0 g

Molar mass of diethyl ether = 74.12 g/mol

Putting values in equation 1, we get:

\text{Moles of diethyl ether}=\frac{208.0g}{74.12g/mol}=2.81mol

Mole fraction of a substance is calculated by using the equation:

\chi_A=\frac{n_A}{n_A+n_B}

\chi_{\text{testosterone}}=\frac{n_{\text{testosterone}}}{n_{\text{testosterone}}+n_{\text{diethyl ether}}}

\chi_{\text{testosterone}}=\frac{0.027}{0.027+2.81}\\\\\chi_{\text{testosterone}}=0.0095

The formula for relative lowering of vapor pressure will be:

\frac{p^o-p_s}{p^o}=i\times \chi_{\text{solute}}

where,

p^o = vapor pressure of solvent (diethyl ether) = 463.57 mmHg

p^s = vapor pressure of the solution = ?

i = Van't Hoff factor = 1 (for non electrolytes)

\chi_{\text{solute}} = mole fraction of solute (testosterone) = 0.0095

Putting values in above equation, we get:

\frac{463.57-p^s}{463.57}=1\times 0.0095\\\\p^s=459.17mmHg

Hence, the vapor pressure of solution is 459.17 mmHg

7 0
3 years ago
How do I complete this column graph of the number of conductors vs the number of insulators
Vikentia [17]

Answer:

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Explanation:

how do I complete this column graph of the number of conduct vs the number of

4 0
3 years ago
Consider the reaction cacn2 + 3 h2o → caco3 + 2 nh3 . how much caco3 is produced if 47.5 moles nh3 are produced? 1. 0.950 g 2. 9
zhannawk [14.2K]
The  CaCO3  produced  if  47.5   moles of  NH3  produced  is   calculated  as  follows

CaCN2  +3H2O  = CaCO3  + 2NH3

by  use   of  mole  ratio  between  CaCO3 to NH3  which  is 1:2  the  moles  of  CaCO3  is therefore =  47.5 /2= 23.75  moles

mass of CaCO3   is  therefore = moles  x  molar  mass
= 23.75 moles  x  100g/mol=  2375 grams   which  is approximate   2380  grams(answer 6)
8 0
4 years ago
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