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Ede4ka [16]
1 year ago
7

3. In AABC, a = 35, c = 25, and m can be drawn given these measurements?

Mathematics
1 answer:
Flauer [41]1 year ago
6 0

Only one triangle possible with angle 38.2° at C.

According to the given statement

we have to seek out that the measurement of m with the help of the a and c.

Then for this purpose, we all know that the

The ambiguous case occurs when one uses the law of sines to see missing measures of a triangle when given two sides and an angle opposite one in every of those angles (SSA).

According to the this law

The equation become

35/sin(60) = 25/sinC

sinC = 0.6185895741

C = 38.2, 141.8

Since 141.8+60 = 201.8 > 180

It will not form a triangle.

So, only 1 triangle possible with angle 38.2° at C

Learn more about ambiguous case here

brainly.com/question/4372174

#SPJ1

Disclaimer: This question was incomplete. Please find the full content below.

Question:

Law of Sines and the Ambiguous Case.

In ∆ ABC, a =35, c = 25, and m < A = 60*

How many distinct triangles can be drawn given these measurements?

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The vertex form of the equation f(x) = x^2 - 3x, is f(x) = (x - 3/2)^2 - 9/5

<h3>How to rewrite the quadratic function?</h3>

The quadratic function is given as:

f(x) = x^2 - 3x

Differentiate the function

f'(x) = 2x - 3

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f(x) = -9/5

So, we have:

(x, f(x)) = (3/2, -9/5)

The above represents the vertex of the quadratic function.

This is properly written as:

(h, k) = (3/2, -9/5)

The vertex form of a quadratic function is

f(x) = a(x - h)^2 + k

So, we have:

f(x) = a(x - 3/2)^2 - 9/5

In f(x) = x^2 - 3x,

a = 1

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f(x) = (x - 3/2)^2 - 9/5

Hence, the vertex form of the equation f(x) = x^2 - 3x, is f(x) = (x - 3/2)^2 - 9/5

Read more about vertex form at

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kobusy [5.1K]

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Step-by-step explanation:

\sqrt{8x+9} =x+2     Square the left and right sides. The square root of 8x+9 squared is 8x+9  and the x+2 squared is x^2 + 4x +4. We will now have the new equation,

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-x^2 +4x + 9 = 4        Finally subtract 4 from both sides

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Now rewrite the whole equation as,

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x(x+1) -5(x+1)= 0      Factor out x+1

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x+1 = 0     or x-5 = 0

   -1    -1          +5   +5

x = -1   or  x = 5

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