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IgorC [24]
1 year ago
8

A conductor is made in the form of a hollow cylinder with inner and outer radii a and b, respectively. It carries a current I, u

niformly distributed over its cross section.
Physics
1 answer:
Nadusha1986 [10]1 year ago
4 0

A conductor is made in the form of a hollow cylinder with inner and outer radii a and b, respectively. It carries a current I, uniformly distributed over its cross section. We are given that

  • Inner radius,
  • Outer radius,
  • Current=I
  • a.If r<a

Consider a loop of radius r where r<a

<h3>What is conductor?</h3>

A conductor is an object or kind of material that permits the movement of charge (electric current) in one or more directions. This term is used in both physics and electrical engineering. Metal-based materials are frequently used as electrical conductors. Negatively charged electrons, positively charged holes, and occasionally positive or negative ions flow to create electric current.

It is not essential for one charged particle to move from the component creating the current (the current source) to those consuming it for current to flow within a closed electrical circuit (the loads). Instead, the charged particle only needs to nuzzle its neighbor a limited number of times, and then the process repeats itself until a particle gets nuzzled into the consumer, generating electricity.

To learn more about conductor from the given link:

brainly.com/question/2290351

#SPJ4

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3 years ago
Who is father of scince​
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Answer:

Galileo

Explanation:

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3 years ago
Read 2 more answers
Three liquids are at temperatures of 4 ◦C, 24◦C, and 29◦C, respectively. Equal masses of the first two liquids are mixed, and th
Scilla [17]

Answer:

T₁₃ = 24.1°C

Explanation:

Given

m = mass of each liquids (all masses are equal)

C₁  = specific heat of the first liquid

C₂ = specific heat of the second  liquid

C₃ = specific heat of the third liquid

T₁ = 4°C (temperature of the first liquid)

T₂ = 24°C  (temperature of the second liquid)

T₃ = 29°C  (temperature of the third liquid)

​Temperature of 1+2 liquids mix: T₁₂ = 21°C

​Temperature of 2+3 liquids mix: T₂₃ = 26.1°C  

Temperature of 1+3 liquids mix: T₁₃ = ?

We can apply the relation ∑Q = 0

We assume the system is isolated and the process is adiabatic.

<u>Mix 1</u>:

Q₁ + Q₂ = 0

where

Q₁ = m*C₁*(T₁-T₁₂)

and

Q₂ = m*C₂*(T₂-T₁₂)

then

m*C₁*(T₁-T₁₂) + m*C₂*(T₂-T₁₂) = 0

⇒ C₁*(T₁-T₁₂) + C₂*(T₂-T₁₂) = 0

⇒ (4°C-21°C)*C₁ + (24°C-21°C)*C₂ = 0

⇒ -17°C*C₁ + 3°C*C₂ = 0

⇒ C₁ = (3/17)*C₂ = 0.176*C₂     (i)

<u>Mix 2</u>:

Q₂ + Q₃ = 0

where

Q₂ = m*C₂*(T₂-T₂₃)

and

Q₃ = m*C₃*(T₃-T₂₃)

then

m*C₂*(T₂-T₂₃) + m*C₃*(T₃-T₂₃) = 0

⇒ C₂*(T₂-T₂₃) + C₃*(T₃-T₂₃) = 0

⇒ (24°C-26.1°C)*C₂  + (29°C-26.1°C)*C₃ = 0

⇒ -2.1°C*C₂ + 2.9°C*C₃ = 0

⇒ C₃ = 0.724*C₂      (ii)

<u>Mix 3</u>:

Q₁ + Q₃ = 0

where

Q₁ = m*C₁*(T₁-T₁₃)

and

Q₃ = m*C₃*(T₃-T₁₃)

then

m*C₁*(T₁-T₁₃) + m*C₃*(T₃-T₁₃) = 0

⇒ C₁*(T₁-T₁₃) + C₃*(T₃-T₁₃) = 0

⇒ (4°C-T₁₃)*C₁ + (29°C-T₁₃)*C₃ = 0

If we use the following relations  C₁ = 0.176*C₂ and C₃ = 0.724*C₂  we obtain

(4°C-T₁₃)*0.176*C₂ + (29°C-T₁₃)*0.724*C₂ = 0

⇒ (4°C-T₁₃)*0.176 + (29°C-T₁₃)*0.724 = 0

⇒ 0.706°C - 0.176*T₁₃ + 21°C - 0.724*T₁₃ = 0

⇒ 0.9*T₁₃ = 21.706°C

⇒ T₁₃ = 24.1°C

5 0
4 years ago
Two gliders collide on a frictionless air track that is aligned along the x axis. Glider A has an initial velocity v0 and glider
LenaWriter [7]

Answer:

Explanation:

Applying conservation of momentum

mA v0 + 0 = mA x 12v0 + mB x 92v0

11 mA = - 92mB .

mA / mB = 92 / 11

mA : mB = 92 : 11.

3 0
3 years ago
A car collides into a concrete wall going 25.0 m/s . It stops in 0.141 seconds and has a change in momentum of 39,400. What is t
vodka [1.7K]

Answer:

Mass of the car is 1576 kg.

Explanation:

Let the mass of the car be m kg.

Given:

Initial velocity of the car is, u=25\ m/s

As the car stops, final velocity of the car is, v=0\ m/s

Change in momentum is, \Delta p=39400

Now, we know that, momentum is given as the product of mass and velocity.

So, change in momentum is given as:

\Delta p=m(u-v)\\39400=m(25-0)\\39400=25m\\m=\frac{39400}{25}\\m=1576\ kg

Therefore, the mass of the car is 1576 kg.

4 0
3 years ago
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