1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Iteru [2.4K]
3 years ago
8

A car collides into a concrete wall going 25.0 m/s . It stops in 0.141 seconds and has a change in momentum of 39,400. What is t

he mass of the car?
Physics
1 answer:
vodka [1.7K]3 years ago
4 0

Answer:

Mass of the car is 1576 kg.

Explanation:

Let the mass of the car be m kg.

Given:

Initial velocity of the car is, u=25\ m/s

As the car stops, final velocity of the car is, v=0\ m/s

Change in momentum is, \Delta p=39400

Now, we know that, momentum is given as the product of mass and velocity.

So, change in momentum is given as:

\Delta p=m(u-v)\\39400=m(25-0)\\39400=25m\\m=\frac{39400}{25}\\m=1576\ kg

Therefore, the mass of the car is 1576 kg.

You might be interested in
2. Sally put her mug of coffee on the table. The mug has a mass of 1 kg. if the pressure
egoroff_w [7]

We have,

  • The mass of sally's mug is 1 kg
  • The pressure appliedby the mug is 1100 pascal.

We know that,

  • Pressure = Force/Area

As, we already have the value of pressure, let's calculate that of force now;

  • F = ma
  • F = 1 × 9.8 { Acceleration due to gravity, let's round off it to 10}
  • F = 10 N

Just put all the values in the formula now;

  • P = F/A
  • 1100 = 10 / A
  • 1100/10 = A
  • 110 m² = A

As, it is already mention that we need to find the radius of the mug, it is obviously a circular base.

We know that,

  • Surface area = Circumference

So, let's solve it;

  • Circumference = 2πr
  • 110 = 2 × 22/7 × r
  • 110 × 7/2 × 22 = r
  • 5 × 7 = r
  • 35 cm = r

<u>T</u><u>h</u><u>u</u><u>s</u><u>,</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>r</u><u>a</u><u>d</u><u>i</u><u>u</u><u>s</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>c</u><u>i</u><u>r</u><u>c</u><u>l</u><u>e</u><u> </u><u>i</u><u>s</u><u> </u><u>3</u><u>5</u><u> </u><u>c</u><u>m</u><u>.</u>

7 0
3 years ago
Arysha enjoys playing lacrosse on the school team. Suppose Arysha throws a lacrosse ball with a force of 6 N, and the resulting
olasank [31]

Answer:

Mass = 0.14kg

Explanation:

Given

Force = 6N

Acceleration = 43m/s^2

Required

Determine the mass of the ball

This question will be answered using Newton's second law of motion.

Which states that

Force = Mass * Acceleration

Substitute values for Force and Acceleration

6N = Mass * 43m/s^2

Make Mass the subject

Mass = \frac{6N}{43m/s^2}

Mass = 0.13953488372

Mass = 0.14kg --- (approximated)

3 0
3 years ago
Rajani had bought a new bottle of pickle from the market. She tried to open the
dem82 [27]

Answer:

The pickle bottle cap on dipping it in hot water expanded.

Explanation: Hope it helps you:))))

Have a good day

4 0
2 years ago
If there is "waste" energy, does the Law of Conservation of Energy still apply? please don't type something random if so i'll ju
FinnZ [79.3K]

Explanation:

Yes, the law of conservation of energy still applies even if there is waste energy.

The waste energy are the transformation products of energy from one form to another.

According to the law of conservation of energy "energy is neither created nor destroyed by transformed from one form to another in a system".

But of then times, energy is lost as heat or sound within a system.

  • If we take into account these waste energy, we can see that energy is indeed conserved.
  • The sum total of the energy generated and those produced will be the same if we factor in other forms in which the energy has been transformed into.
8 0
3 years ago
A uniform meter rule of weight 0.9N is suspended horizontally by two vertical loops of thread A and B placed 20cm and 30cm from
Rzqust [24]

The  distance from the centre of the rule at which a 2N weight must be suspend from A is 29.3 cm.

<h3>Distance from the center of the meter rule</h3>

The distance from the centre of the rule at which a 2N weight must be suspend from A is calculated as follows;

-----------------------------------------------------------------

  20 A  (30 - x)↓      x         ↓      20 cm  B 30 cm

                       2N              0.9N

Let the center of the meter rule = 50 cm

take moment about the center;

2(30 - x) + 0.9(x)(30 - x) = 0.9(20)

(30 - x)(2 + 0.9x) = 18

60 + 27x - 2x - 0.9x² = 18

60 + 25x - 0.9x² = 18

0.9x² - 25x - 42 = 0

x = 29.3 cm

Thus, the  distance from the centre of the rule at which a 2N weight must be suspend from A is 29.3 cm.

Learn more about brainly.com/question/874205 here:

#SPJ1

7 0
2 years ago
Read 2 more answers
Other questions:
  • A no-start condition is being discussed on an engine equipped with a waste spark ignition system.
    10·1 answer
  • A photon has a wavelength of 781 nm. Calculate the energy of the photon in joules. Enter your answer in scientific notation.
    14·1 answer
  • A=vf-vi/t solve for vi
    10·1 answer
  • How many milliliters of water at 25.0°C with a density of 0.997 g/mL must be mixed with 162 mL of coffee at 94.6°C so that the r
    11·1 answer
  • While a block slides forward 1.35 m, a force pulls back at a 135 direction, doing -17.8 J of work. what is the magnitude of the
    12·1 answer
  • In a normal atom, how many electrons are there compared with protons?
    14·1 answer
  • State the number of electrons and protons found in an neutral atom
    7·1 answer
  • Lake is home to a large number of trout. Identify what is most likely to happen if a chemical is dumped into the lake. It is a s
    5·1 answer
  • The difference between an electric motor and an electric generator is that a motor converts _______ energy into energy _______,
    9·2 answers
  • Find the value of the spring constant for the spring in Trial I. Use 0.367 s for the value of the period. The mass of the suspen
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!