We have,
- The mass of sally's mug is 1 kg
- The pressure appliedby the mug is 1100 pascal.
We know that,
As, we already have the value of pressure, let's calculate that of force now;
- F = ma
- F = 1 × 9.8 { Acceleration due to gravity, let's round off it to 10}
- F = 10 N
Just put all the values in the formula now;
- P = F/A
- 1100 = 10 / A
- 1100/10 = A
- 110 m² = A
As, it is already mention that we need to find the radius of the mug, it is obviously a circular base.
We know that,
- Surface area = Circumference
So, let's solve it;
- Circumference = 2πr
- 110 = 2 × 22/7 × r
- 110 × 7/2 × 22 = r
- 5 × 7 = r
- 35 cm = r
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Answer:

Explanation:
Given


Required
Determine the mass of the ball
This question will be answered using Newton's second law of motion.
Which states that

Substitute values for Force and Acceleration

Make Mass the subject


--- (approximated)
Answer:
The pickle bottle cap on dipping it in hot water expanded.
Explanation: Hope it helps you:))))
Have a good day
Explanation:
Yes, the law of conservation of energy still applies even if there is waste energy.
The waste energy are the transformation products of energy from one form to another.
According to the law of conservation of energy "energy is neither created nor destroyed by transformed from one form to another in a system".
But of then times, energy is lost as heat or sound within a system.
- If we take into account these waste energy, we can see that energy is indeed conserved.
- The sum total of the energy generated and those produced will be the same if we factor in other forms in which the energy has been transformed into.
The distance from the centre of the rule at which a 2N weight must be suspend from A is 29.3 cm.
<h3>Distance from the center of the meter rule</h3>
The distance from the centre of the rule at which a 2N weight must be suspend from A is calculated as follows;
-----------------------------------------------------------------
20 A (30 - x)↓ x ↓ 20 cm B 30 cm
2N 0.9N
Let the center of the meter rule = 50 cm
take moment about the center;
2(30 - x) + 0.9(x)(30 - x) = 0.9(20)
(30 - x)(2 + 0.9x) = 18
60 + 27x - 2x - 0.9x² = 18
60 + 25x - 0.9x² = 18
0.9x² - 25x - 42 = 0
x = 29.3 cm
Thus, the distance from the centre of the rule at which a 2N weight must be suspend from A is 29.3 cm.
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