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Iteru [2.4K]
3 years ago
8

A car collides into a concrete wall going 25.0 m/s . It stops in 0.141 seconds and has a change in momentum of 39,400. What is t

he mass of the car?
Physics
1 answer:
vodka [1.7K]3 years ago
4 0

Answer:

Mass of the car is 1576 kg.

Explanation:

Let the mass of the car be m kg.

Given:

Initial velocity of the car is, u=25\ m/s

As the car stops, final velocity of the car is, v=0\ m/s

Change in momentum is, \Delta p=39400

Now, we know that, momentum is given as the product of mass and velocity.

So, change in momentum is given as:

\Delta p=m(u-v)\\39400=m(25-0)\\39400=25m\\m=\frac{39400}{25}\\m=1576\ kg

Therefore, the mass of the car is 1576 kg.

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The ion at the center of a silicate tetrahedron is surrounded by ________.
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Oxygen....................
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2 years ago
A single point on a distance time graph tells the
Sonbull [250]

Answer: Instantaneous speed.

Explanation:

4 0
3 years ago
Two identical small charged spheres hang in equilibrium with equal masses (0.02kg). The length of the strings is equal (0.18m) a
Yuliya22 [10]

Answer:

The value is q = 3.4 *10^{-6} \ C

Explanation:

From the question we are told that

    The mass of each sphere is m_1 = m_2  = m  =  0.020 \ kg

     The length of the string is  l = 0.18 \  m

     The angle of with the vertical is \theta  =  7^o

      The acceleration due to gravity is g = 9.8 \ m/s^2

Generally the force acting between the forces is mathematically represented as

       F  =  T cos \theta =  \frac{k*  q^2}{ r^2}

=>     T cos \theta =  \frac{k*  q^2}{ r^2}

Generally from Pythagoras theorem the radius of the circular curve created by the force is

         r = 2 L sin (\theta )

=>      r = 2* 0.180 sin (7)

=>      r = 0.043 \ m  

=>     q = tan \theta * \frac{m * g * r^2 }{k}

=>      q = tan(7)* \frac{ 0.02 * 9.8 * 0.043^2 }{9*10^{9}}

=>      q = 3.4 *10^{-6} \ C

7 0
3 years ago
Now consider a wave which is paired with seven other waves into seven pairs. The two waves in each pairing are identical, except
kupik [55]

The pair BCEG will interfere constructively, while the pair ADF will interfere destructively.

Constructive and destructive interference:

For interference, the waves must be coherent.

Two coherent waves interfere constructively when the path difference is equal to an integral multiple of the wavelength.

That is the path difference must be mλ

where m = 0,1,2,3.... is an integer and λ is the wavelength

So pair BCEG interfere constructively

Two coherent waves interfere destructively when the path difference is equal to a half-integral multiple of the wavelength.

That is the path difference must be (m+1/2)λ

where m = 0,1,2,3....   is an integer and λ is the wavelength

Therefore, the interference is in the pair ADF which is interfere destructively.

Learn more about interference: brainly.com/question/1194044

#SPJ4

[NOTE: THE COMPLETE QUESTION IS:

Now consider a wave which is paired with seven other waves into seven pairs. The two waves in each pairing are identical, except that one of them is shifted relative to the other in the pair by the distance shown: A. -(1/2) ?B. 2?C. -5?D. (3/2)?E. 0F. (17/2)?G. (6/2)?Identify which of the seven pairs will interfere constructively and which will interfere destructively. Each letter represents a pair of waves. Enter the letters of the pairs that correspond to constructive interference in alphabetical order and the letters of the pairs that correspond to pairs that interfere destructively in alphabetical order separated by a comma. For example if pairs A, B and D interfere constructively and pairs C and F interfere destructively enter ABD,CF.]

4 0
1 year ago
Read 2 more answers
after a large snowstorm you shovel 2000 kilograms of snow off your side walk in 1 hour. you lift the shovel to an average height
solmaris [256]

Lifting a mass to a height, you give it gravitational potential energy of

       (mass) x (gravity) x (height)  joules.

To give it that much energy, that's how much work you do on it.

If 2,000 kg gets lifted to 1.25 meters off the ground, its potential energy is

         (2,000) x (9.8) x (1.25) = 24,500 joules.

If you do it in 1 hour (3,600 seconds), then the average power is

           (24,500 joules) / (3,600 seconds) = 6.8 watts.

None of these figures depends on whether the load gets lifted all at once,
or one shovel at a time, or one flake at a time.

But this certainly is NOT all the work you do.  When you get a shovelful
of snow 1.25 meters off the ground, you don't drop it and walk away, and
it doesn't just float there. You typically toss it, away from where it was laying
and over onto a pile in a place where you don't care if there's a pile of snow
there. In order to toss it, you give it some kinetic energy, so that it'll continue
to sail over to the pile when it leaves the shovel.  All of that kinetic energy
must also come from work that you do ... nobody else is going to take it
from you and toss it onto the pile.


8 0
3 years ago
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