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Iteru [2.4K]
3 years ago
8

A car collides into a concrete wall going 25.0 m/s . It stops in 0.141 seconds and has a change in momentum of 39,400. What is t

he mass of the car?
Physics
1 answer:
vodka [1.7K]3 years ago
4 0

Answer:

Mass of the car is 1576 kg.

Explanation:

Let the mass of the car be m kg.

Given:

Initial velocity of the car is, u=25\ m/s

As the car stops, final velocity of the car is, v=0\ m/s

Change in momentum is, \Delta p=39400

Now, we know that, momentum is given as the product of mass and velocity.

So, change in momentum is given as:

\Delta p=m(u-v)\\39400=m(25-0)\\39400=25m\\m=\frac{39400}{25}\\m=1576\ kg

Therefore, the mass of the car is 1576 kg.

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2. Sally put her mug of coffee on the table. The mug has a mass of 1 kg. if the pressure
egoroff_w [7]

We have,

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We know that,

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As, we already have the value of pressure, let's calculate that of force now;

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Just put all the values in the formula now;

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As, it is already mention that we need to find the radius of the mug, it is obviously a circular base.

We know that,

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So, let's solve it;

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  • 110 = 2 × 22/7 × r
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7 0
3 years ago
(a) two protons in a molecule are 4.50 10-10m apart. find the magnitude of the electric force exerted by one proton on the other
Anuta_ua [19.1K]

Answer:

a)  1. 1365 × 10⁻⁹N

b) 9.1862 × 10⁻⁴⁶N

c) 8.61 × 10⁻¹¹C/Kg

Explanation:

Ke = 8.99× 109 N.m2 / C2 ,      G = 6.67 × 10-11 N. m2 / kg2

a)  F = Ke . q₁.q₂/r²  

=  (8.99× 109 N.m2 / C2 ) ×(1.60×10⁻¹⁹C)²/(4.50×10⁻¹⁰C)²

= 1. 1365 × 10⁻⁹N

b)  

F = Gm₁m₂/r²

= (6.67× 10⁻¹¹)×(1.67×10⁻²⁷)²/(4.50×10⁻¹⁰)²

= 9.1862 × 10⁻⁴⁶N

The electric force is larger by 8.0497 ×10³⁷ times

c)

if Keq₁q₂/r² Gm₁m₂/r²,

with q₁=q₂ = q,  and m₁ =m₂ = m

Then q/m =\sqrt{G/M} = \sqrt{(6.67 X 10^{-11} } /8.89 X 10^{9}

= 8.61 × 10⁻¹¹C/Kg

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Answer:

1.67m/s

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Speed=Distance/Time

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3 0
3 years ago
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