Answer:
A.) 42.7 m/s
B.) 0.33 m/s^2
C.) 90 kg
Explanation:
A.) If Justin races his Chevy S-10 down highway 37 north for 2,560 meters in 60 seconds, what is his velocity?
Velocity = displacement/time
Velocity = 2560/60
Velocity = 42.67 m/s
B.) The Chevy S-10 started rounding at 10 meters per hour. What is the acceleration at 30 seconds on the highway?
Acceleration = velocity/time
Acceleration = 10/30
Acceleration = 0.33 m/s^2
C.) The S-10 has a force of 30 N. What is the mass of the car?
Force = mass × acceleration
30 = mass × 0.33
Mass = 30/ 0.33
Mass = 90 kg
The correct answer would be B.
According to Newton's 2nd law of motion:
F = m * a where F is the force applied in Newtons, m is the mass of the object in kg, and a is the acceleration of the object in m/

.
Therefore the force applied in this situation is simply:
F = 6 kg * 2.3 m/

= 13.8 N
Hope this helps!
Answer:
324795 C
252.637820565 N/C

Explanation:
= Permittivity of free space = 
R = Radius of Mars = 
A = Area = 
= Electric flux = 
Electric flux is given by

The charge is 324795 C
Electric field is given by

The electric field is 252.637820565 N/C
Surface charge density is given by

The surface charge density is 
Answer:
kinda
Explanation:
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