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Virty [35]
1 year ago
12

Can someone provide a answer with explanation for this question? Thanks!

Chemistry
1 answer:
zhuklara [117]1 year ago
4 0

Answer:

Explanation:

B

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If your lawn is 21.0 ft wide and 20.0 ft long, and each square foot of lawn accumulates 1350 new snow flakes every minute. How m
klemol [59]
Let us start with the total area of the lawn. Area= width x length, ie, 21 x 20 = 420 sq. ft.   Snow flakes per square foot per minute = 1350  So Snow flakes for 420 sq.feet per minute = 420 x 1350 = 567000.   Snow flakes for 1 hour = 567000 x 60 = 34020000 (60 minutes)  Weight of 34020000 snow flakes = 34020000 x 1.60 = 54432000mg.  To convert it into kilograms, divide this number by 1000000 (1 kilogram = 1000000 milligrams)  Thus 54432000/1000000 = 54.432 kilograms or 54 kilograms and 432 grams.
6 0
3 years ago
LINKING IN<br> TECHNICAL OBJECTS<br> 1 a) What is linking?
d1i1m1o1n [39]

Answer:

A link is a fastening unit that attaches two parts of an object together

Different types of links have different characteristics

4 0
3 years ago
Read 2 more answers
An aqueous solution is listed as being 33.8% solute by mass with a density of 1.15 g/mL, the molar mass of the solute is 145.6 g
vodomira [7]

Answer:

A) 2.69 M

B) 0.059

Explanation:

A) We have:

33.8% solute by mass= 33.8 g solute/100 g solution

molarity = mol solute/ 1 L solution

molarity= \frac{33.8 g solute}{100 g solution} x \frac{1.15 g solution}{1 ml} x \frac{1 mol solute}{145.6 g solute} x \frac{1000 ml}{1 L}

molarity= 2.69 mol solute/L solution = 2.69 M

B) We know that there are 33.8 g of solute in 100 g of solution.

As the total solution is compounded by solute+solvent (in this case, solvent is water), the mass of water is the difference between the mass of the total solution and the mass of solute:

mass of water= 100 g - 33.8 g = 66.2 g

Now, we calculate the number of mol of both solute and water:

mol solute= 33.8 g solute x \frac{1 mol solute}{145.6 g} = 0.232 mol

mol H20= 66.2 g H₂O x \frac{1 mol H2O}{18 g}

Finally, the mol fraction of solute (Xsolute) is calculated as follows:

Xsolute=\frac{mol solute}{total mol}= \frac{mol solute}{mol solute + mol H2O}=\frac{0.232 mol}{0.232 mol + 3.677 mol}

Xsolute= 0.059

4 0
3 years ago
Precipitation reactions: Hg(NO3)2(aq) +Na2CrO4(aq) = _________ (aq) + NaNO3 (s)
valina [46]
The completed and balanced equation is:
<span>Hg(N<span>O3</span><span>)2</span>+N<span>a2</span>Cr<span>O4</span>=HgCr<span>O4</span>+2Na(N<span>O3</span>)
Hope this helps :)</span>
5 0
3 years ago
How does the overall charge of oxygen of -16 compare to the overall charge of oxygen -17 and oxygen -18?
nadezda [96]

Answer:

-2

The charge on an oxygen ion is -2. An oxygen atoms contain six electrons in its valence electron shell.

Explanation:

5 0
3 years ago
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