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suter [353]
3 years ago
5

To form an oxygen molecule o2 two oxygen atoms share two pairs of electrons what kind of bond is shown below by the electron dot

diagram of o2
Chemistry
2 answers:
Alexus [3.1K]3 years ago
7 0
They have a Covelant bond
Dima020 [189]3 years ago
4 0

it is a covalent bond.

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NaOH (aq) + H2SO4 (aq) > H2O + NaSO4 (aq)
Elden [556K]

Answer:

2 NaOH (aq) + H_2SO_4 (aq)\rightarrow 2 H_2O (l) + Na_2SO_4 (aq)

Explanation:

Let's correct and balance the given equation:

  • NaOH (aq) is sodium hydroxide, charge of sodium is +1, charge of hydroxide is -1, so it's fine;
  • H_2SO_4 (aq) is sulfuric acid, charge of hydrogen cation is +1, charge of sulfate is -2, sulfate is balanced by the two protons;
  • H_2O (l) is firstly a molecule, it's water, in its liquid state, the oxidation state of +1 for the two hydrogens is balanced by the oxidation state of -2 for oxygen;
  • sodium sulfate should be Na_2SO_4 (aq), since sulfate has a charge of -2, this would require two sodium cations to balance it.

The equation becomes:

NaOH (aq) + H_2SO_4 (aq)\rightarrow H_2O (l) + Na_2SO_4 (aq)

We require 2 NaOH in order to balance the two sodium cations on the right, this would yield a total of 4 hyrogens on the left, so we also need two water molecules to balance it fully:

2 NaOH (aq) + H_2SO_4 (aq)\rightarrow 2 H_2O (l) + Na_2SO_4 (aq)

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