Answer:
what is this I am not getting which type of this question you have taken from where
Answer: 510 L of oxygen gas were consumed.
Explanation:
According to ideal gas equation:
P = pressure of gas = 750 torr = 0.99 atm (760 torr= 1atm)
V = Volume of gas = 620 L
n = number of moles of carbon dioxide = ?
R = gas constant =
T =temperature =
According to stoichiometry:
8 moles of are produced by = 13 moles of oxygen
Thus 9.08 moles of are produced by = moles of oxygen
P = pressure of gas = 540 torr = 0.71 atm (760 torr= 1atm)
V = Volume of gas = ?
n = number of moles of oxygen = 14.8
R = gas constant =
T =temperature =
Thus 510 L of oxygen gas were consumed.
Since HCl is a strong acid, it readily dissociates, so we can assume that there are 1.0x10^-3 M of H+ ions. We can use the formula:
pH=-log[H+]
pH=-log(1.0x10^-3)
pH=3
We can find the pOH by subtracting 14-pH:
14-3=11
pOH=11
The [OH-] can be found by using the formula:
pOH=-log[OH-]
11=-log[OH-]
10^-11=[OH-]
[OH-]=1.0x10^-10
Answer:
250cm³ de disolución se deben preparar
Explanation:
El porcentaje volumen volumen (%v/v) se define como el volumen de soluto -En este caso, H2O2- en 100cm³ de disolución.
Se desea preparar una solución que contenga 20cm³ de H2O2 por cada 100cm³
Como solamente se cuenta con 50cm³ de H2O2, el volumen que se debe preparar es:
50cm³ H2O2 * (100cm³ Disolución / 20cm³ H2O2) =
<h3>250cm³ de disolución se deben preparar</h3>