1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vlabodo [156]
1 year ago
7

A compound is discovered and its molecular weight is determined to be 526g/mol. however, one of the elements has not yet been id

entified. what is the missing element, x, in batio9(x7)?
Physics
1 answer:
AfilCa [17]1 year ago
7 0

Sulphur

The missing element is sulphur

Here the compound is composed of  element X and chlorine.

it is given,

XCl (6) ----> 6Cl

mass = 13.1%

it is X and Cl = 100%-13.10%

                     = 86.90%

chlorine = 86.90            

X = 13.10

We assume 100g of sample

so according to the above solved data, in 100g of sample we have 86.90 g of chlorine.

now we split that chlorine into two moles of chlorine.

  • Every mole of sale has 35.45 grams of sales. 2.451 moles of seal are mine after that.
  • We are aware that cl is six times more than X. To find the moles of X, I must divide this number by six.
  • we discover that we have  0.4086 moles of X when we divide this by six.
  • We obtain those moles of X from 13.10 g of X.  
  • Given that Mueller masses grams per mole, I can compute the molar mass.
  • 13.10 grams of X are contained in 0.4086 moles of X.
  • Or, to put it another way, each remote has a molar mass of 32–06 grams.
  • The element with this molar mass is sulfur, as I can see from the periodic table.
  • Okay, so the element we're looking for in this situation is sulfur.

To learn more about finding missing element visit;

brainly.com/question/14238796

#SPJ4

You might be interested in
On the Moon's surface, lunar astronauts placed a corner reflector, off which a laser beam is periodically reflected. The distanc
Arisa [49]

Answer:

Explanation:

The difference in time will be due to travel through atmosphere where speed of light slows down. If t be the thickness of atmosphere and c be the speed of light in space and μ be the refractive index of atmosphere difference in travel time will be as follows .

difference = \frac{2t\mu }{c}-\frac{2t }{c}

=\frac{2t}{c }\left ( 1-\mu  \right )

Now t = 40 x 10³m ,μ = 1.000293 , c = 3 x 10⁸.

difference =\frac{2t\mu }{c}-\frac{2t }{c}

=\frac{2t}{c }\left ( \mu -1  \right )\\

=\frac{ 2\times 40\times 10^3}{3\times10^3 }\left ( 1.000293-1 \right )\\

=7.81\times 10^{-3} s

4 0
3 years ago
Thomas is climbing Mt. Everest. What happens as he climbs farther up the mountain?
lakkis [162]

Answer:

B. the air pressure decreases

Explanation:

As elevation increases, there is less overlying atmospheric pressure mass, so that atmospheric pressure decreases with increasing elevaton.

4 0
3 years ago
Read 2 more answers
The process in which acids and bases react so that the properties of both are lost to form water and a salt is called __________
makvit [3.9K]
The process is called neutralization.
Hope this helps!
4 0
3 years ago
A 6,000 kg train car is moving to the right at 10 m/s and connects to a 4,000-kg train car that wasn't moving. What is the veloc
vredina [299]

1) The final velocity of the two trains is 6 m/s to the right

2) It is an inelastic collision

Explanation:

1)

We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the two trains must be conserved before and after the collision.

Therefore we can write:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 = 6,000 kg is the mass of the first train

u_1 = 10 m/s is the initial velocity of the first train

m_2 = 4,000 kg is the mass of the second train

u_2 = 0 is the initial velocity of the second train  (initially at rest)

v is the final combined velocity of the two trains

Solving the equation for v, we find the final velocity of the two trains:

v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{(6000)(10)+0}{6000+4000}=6 m/s

2)

There are two types of collisions:

  • Elastic collision: in an elastic collision, both the total momentum and the total kinetic energy of the system are conserved
  • Inelastic collision: in an inelastic collision, only the total momentum is conserved, while the total kinetic energy is not (part of it is converted into thermal energy due to internal frictions)

To verify what type of collision is this, we can compare the total kinetic energy before and after the collision:

Before:

K=\frac{1}{2}m_1 u_1^2 = \frac{1}{2}(6000)(10)^2=300,000 J

After:

K=\frac{1}{2}(m_1 +m_2)v^2 = \frac{1}{2}(6000+4000)(6)^2=180,000 J

As we can see, the kinetic energy is not conserved, so this is an inelastic collision.

Learn more about momentum here:

brainly.com/question/7973509  

brainly.com/question/6573742  

brainly.com/question/2370982  

brainly.com/question/9484203  

#LearnwithBrainly

3 0
3 years ago
The equation for free fall at the surface of a celestial body in outer space​ (s in​ meters, t in​ seconds) is sequals10.04tsqua
Sindrei [870]

Answer:

1.42 s

Explanation:

The equation for free fall of an object starting from rest is generally written as

s=\frac{1}{2}at^2

where

s is the vertical distance covered

a is the acceleration due to gravity

t is the time

On this celestial body, the equation is

s=10.04 t^2

this means that

\frac{1}{2}g = 10.04

so the acceleration of gravity on the body is

g=2\cdot 10.04 = 20.08 m/s^2

The velocity of an object in free fall starting from rest is given by

v=gt

In this case,

g = 20.08 m/s^2

So the time taken to reach a velocity of

v = 28.6 m/s

is

t=\frac{v}{g}=\frac{28.6 m/s}{20.08 m/s^2}=1.42 s

3 0
3 years ago
Other questions:
  • You walk with a velocity of 2 m/s north. You see a man approaching you, and from your frame of reference he has a speed of 3 m/s
    11·1 answer
  • Three identical 50-kg masses are held at the corners of an equilateral triangle, 30 cm on each side. If one of the masses is rel
    11·1 answer
  • A ball is launched at an angle of 39.8 degrees up from the horizontal, with a muzzle velocity of 6.6 meters per second, from a l
    5·1 answer
  • mass is tied to spring and begins periodically . the distance between its highest and its lowest position is 48cm. what is the a
    15·1 answer
  • 6. Which of the following is the force needed to make a 1-kg object accelerate at 1 m/s??
    7·2 answers
  • 3. A woman drove her car from home to her daughter's school. The odometre on her dashboard says she travelled 4.5 km to do this.
    15·1 answer
  • How can I solve this?
    6·1 answer
  • 6. traction a. friction between a tire and the road.b. pushes a moving object out of a curve and into a straight linec. the abil
    15·1 answer
  • The___ of a mirror's surface determines the type of image it forms.
    7·1 answer
  • How can spectroscopy and infrared technology be useful in space? (5 points)
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!