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3 years ago

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3. When two liquids are mixed and a solid

1 answer:

Mnenie [13.5K]3 years ago

5 0

Answer: A; Precipitate

Explanation:

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two masses are separated by 1 m. suppose the masses are moved so they are 2 m apart how will the gravitational force change

Verdich [7]

The gravitational force would get stronger because the farther the two masses are separated the more gravitational force will be used to pull them together the closer they are the less gravitational pull is used to pull them together

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3 years ago

As a pendulum swings from its highest to lowest position, what happens to its kinetic and potential energy?

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The potential energy decreases while the kinetic energy increases.

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A concave lens has a focal length of 25cm. it's power in diaptor is

IgorLugansk [536]

As we know that :

$\begin{gathered}\large{\boxed{\sf{P \: = \: \dfrac{1}{f}}}} \\ \\ \rightarrow {\sf{P \: = \: \dfrac{1}{-25}}}\end{gathered}$

Power, is in Meter. So divide focal length by 100

$\begin{gathered}\rightarrow {\sf{P \: = \: \dfrac{1}{\dfrac{-25}{100}}}} \\ \\ \rightarrow {\sf{P \: = \: \dfrac{-100}{25}}} \\ \\ \rightarrow {\sf{P \: = \:- 4}} \\ \\ \underline{\sf{\therefore \: Power \: of \: Concave \: lens \: is \: - \: 4D}}\end{gathered}$

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1 year ago

In the Biomedical and Physical Sciences building at MSU there are 135 steps from the ground floor to the sixth floor. Each step

satela [25.4K]

Answer:

W = 16.5 Kj

P = 49.9 Watt

E = 16471

Explanation:

m = 73.5kg

t = 5min 30sec = (5×60) + 30 = 330sec

each step = 16.6cm = 0.166m

h = 135×0.166 = 22.41 m

g = 10 m/s²

(i) W = F × s = W × h = mgh

W = 73.5×10×22.41 = 16471.35

W = 16.5 Kj

(ii) Power = workdone/time

P = 16471.35/330

P = 49.9 Watt

(iii) The energy burnt in this process = 16471

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3 years ago

You are inside a room, 15 m from the west wall, which has two doors (similar to slits) and you are centered between the two open

andre [41]

Answer:

The distance of first minimum from central maxima is 4.25 m

The spacing between maxima in sound intensity is 8.5 m.

Explanation:

Given that,

Distance D= 15 m

Frequency = 200 Hz

distance between slits a=3 m

We know that,

The width of fringe,

$\beta=\dfrac{\Lambda D}{a}$

$\beta=\dfrac{vD}{fa}$

(a). We need to calculate the distance of first minimum from central maxima

Using formula for distance

$d=\dfrac{\beta}{2}$

$d=\dfrac{vD}{2fa}$

Put the value into the formula

$d=\dfrac{340\times15}{2\times200\times3}$

$d=4.25\ m$

(b). We need to calculate the spacing between maxima in sound intensity

Using formula for the distance of first maxima

$d'=2d$

$d'=2\times4.25$

$d'=8.5\ m$

Hence, The distance of first minimum from central maxima is 4.25 m

The spacing between maxima in sound intensity is 8.5 m.

6 0

3 years ago