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3 years ago

. A force of 3.0 N acts through a distance of 12 m in

Physics

1 answer:

musickatia [10]3 years ago

6 0

Answer:

<h3>The answer is 36 J</h3>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 3 × 12

We have the final answer as

Hope this helps you

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Why is it important that two different metals are used in building an electrochemic<br> cell?

Mnenie [13.5K]

Answer:

Explanation:

They need a galvanic difference. Or saying that less technically, they need to have different electron attraction, so that one can collect electrons (oxidation/reduction) and flow current from the other. :)

5 0

3 years ago

If magnet A can pick up 3 steel paper clips and magnet B can pick up 11 gold paper clips and which one is stronger?

Nutka1998 [239]

The answer to your question is b

8 0

3 years ago

0.180-kg stone rets on a frictionless, horizontal surface. A bullet of mass 7.50 g, traveling horizontally at 390 m/s, strikes t

Musya8 [376]

Answer:

The magnitud of the velocity is

$8.46m/s$

and the direccion:

$-28.3$ degrees from the horizontal.

Explanation:

Fist we define our variables:

$m_{s}=0.18kg\\m_{b}=7.5g = 0.0075kg\\v_{1b}= 390m/s -i\\v_{1s}=0m/s\\v_{2b}=210m/s -j\\v_{2s}=?$

The letters i and j represent the direction of the movement, i in this case is the horizontal direction, and j is perpendicular to i.

velocities with sub-index 1 are the speeds before the crash, and with sub-index 2 are the velocities after the crash.

Using conservation of momentum:

$m_{s}v_{1s}+m_{b}v_{1b}=m_{s}v_{2s}+m_{b}v_{2b}\\v_{1s}=0, so\\m_{b}v_{1b}=m_{s}v_{2s}+m_{b}v_{2b}$

Clearing for the velocity of the stone after the crash:

$v_{2s}=\frac{m_{b}v_{1b}-m_{b}v_{2b}}{m_{s}}$

Substituting known values:

$v_{2s}=\frac{0.0075kg(((390m/s-i)-210m/s-j)}{0.18kg}\\v_{2s}=(16.25m/s-i) - (8.75m/s-j)$

The magnitud of the velocity is :

$|v_{2s}|=\sqrt{(16.25m/s-i)^2 + (8.75m/s-j)^2}\\|v_{2s}|=18.46m/s$

and the direction:

$tan^{-1}(-8.75/16.25)=-28.3$

this is -28.3 degrees from the +i direction or the horizontal direcction.

Note: i and j can also be seen as x and y axis.

3 0

4 years ago

Force (N) = 250<br> Mass (kg) = 221<br> Acceleration (m/s^2) = ?

lyudmila [28]

Answer:

The required acceleration is $a=1.1$ m/s²

Explanation:

Given

Force F = 250 N

Mass m = 221 kg

To determine

Acceleration a = ?

We know that acceleration is produced when a force is applied to a body.

The acceleration can be determined using the formula

$F = ma$

where

F is the force

m is the mass

a is the acceleration

now substituting F = 250 , and m = 221 in the formula

$F = ma$

$250 = 221 (a)$

switch the equation

$221(a) = 250$

Divide both sides by 221

$\frac{221a}{221}=\frac{250}{221}$

simplify

$a=\frac{250}{221}$

$a=1.1$ m/s²

Therefore, the required acceleration is $a=1.1$ m/s²

8 0

3 years ago

Do non metals have luster

puteri [66]

Yes, It probably true. Because the Luster it has a nonmetal, is going to be found in periodic table.

Hope it helped you.

-Charlie

4 0

3 years ago