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Thepotemich [5.8K]
3 years ago
14

. A force of 3.0 N acts through a distance of 12 m in

Physics
1 answer:
musickatia [10]3 years ago
6 0

Answer:

<h3>The answer is 36 J</h3>

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 3 × 12

We have the final answer as

<h3>36 J</h3>

Hope this helps you

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which of these chemical formulas represents two elements whose atoms have joined together with an ionic bond? A. O2 B. CaO C.NeN
cupoosta [38]
B: CaO
Because Calcium is a Metal and Oxygen is a Non-Metal. Ionic bonds are only formed with a Metal and a Non-Metal element.
3 0
3 years ago
If a car accelerates uniformly from rest to 15 meters
Talja [164]

Answer:

1.125m/s^2

Explanation:

Since acceleration is defined as the rate of change in velocity with respect to time. Mathematically

v^2= u^2+2as

Where a,v,u and s are the acceleration, final velocity, initial velocity and distance respectively.

a = ?

u = 0m/s

v = 15m/s

s = 100m

Substituting the values into the formula above

v^2= u^2+2as

15^2=0^2+2×a×100

225= 0+200a

225= 200a

Divide both sides by 200

225/200 = 200a/200

a= 1.125m/s^2

Hence the acceleration of the car is 1.125m/s^2.

Note that the car accelerated uniformly from rest, that was why the initial velocity was 0m/s

8 0
3 years ago
Read 2 more answers
Hello,Plz Help Which conditions are necessary for rain to form?
dimulka [17.4K]
Vas happenin!
The third one makes no since because the clouds carry the rain. It isn’t always cold when it’s going to rain

The fourth one is a good one

The second one again it’s not always cold when it’s raining

The first one could be it also

Hmmm I would go with the last one

Sorry if it’s wrong
5 0
3 years ago
How do i turn 36 m/s into mph
gayaneshka [121]

Answer:

me no speak d english

Explanation:

5 0
3 years ago
Rick shoots a basketball at an angle of 35' from the horizontal. It leaves his hands 7 feet from the ground with a velocity of 2
Korvikt [17]

Given:

The angle of projection of the basketball, θ=35°

The height at which the ball leaves the hand, h=7 ft

The initial velocity of the basketball, v=20 ft/s

To find:

The parametric equations describing the shot.

Explanation:

The range, x of the basketball is given by,

x=v\cos\theta t

On substituting the known values,

\begin{gathered} x=20\times\cos35\degree\times t \\ \implies x=16.4t \end{gathered}

The change in the height, y of the basketball is given by,

y=-v\sin\theta t+\frac{1}{2}gt^2

Where g is the acceleration due to gravity.

On substituting the known values,

\begin{gathered} y=-20\times\sin35\degree\times t+\frac{1}{2}\times32\times t^2 \\ \implies y=-11.5t+16t^2 \end{gathered}

Final answer:

The parametric equations describing the shot are

\begin{gathered} \begin{equation*} x=16.4t \end{equation*} \\ \begin{equation*} y=-11.5t+16t^2 \end{equation*} \end{gathered}

8 0
1 year ago
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