Answer:
0.212V
Explanation:
The induced emf in circular loop is
N = Number of loops = 15
A = Cross sectional Area = 
= 0.0009
dB = change in magnetic Field = 0-0.5 = -0.5
dt = time taken = 0.1sec
= 0.212V
Answer:
Cat with 6 kg sitting on a 30 meter hill has greater potential energy.
Explanation:
gravitational potential energy (J) = mass (kg) × gravitational field × height (m)
<h3 /><h3><u>Note</u>:</h3>
gravitational field in Earth is 10 N/kg = <u>fixed unit</u>
<h3 /><h3><u>Given</u>:</h3>
1st Cat: 4 kg
2nd Cat: 6 kg
Both of their height is 30 meters.
<h3><u>Solve for g.p.e</u>:</h3>
1st cat = mgh = 4 × 10 × 30 = 1200 Joules
2nd cat = mgh = 6 × 10 × 30 = 1800 Joules
Answer:
The height of the airplane is 3312.4 meters.
Explanation:
Given that,
Speed of the airplane, v = 1100 km/h = 300 m/s
It takes 26 s for the engine to hit the ground. We need to find the height of the airplane. Using second equation of motion to find it as :

Here, u = 0 and a = g

The height of the airplane is 3312.4 meters.