Answer:
10.5grams
Explanation:
Molarity = number of moles (n)/ volume (V)
According to this question;
Volume = 750 mL = 750/1000 = 0.75L
Molarity = 0.35M
number of moles (n) = molarity × volume
n = 0.35 × 0.75
n = 0.2625mol
Using mole = mass/molar mass
Molar Mass of NaOH = 23 + 16 + 1
= 40g/mol
mole = mass/molar mass
0.2625 = mass/40
mass = 10.5grams
10.5 grams are needed to prepare 0.75L of a 0.35 M solution of NaOH.
Answer:- 3.84 grams
Solution:- Volume of the sample is 44.8 mL and the density is 1.03 gram per mL.
From the density and volume we calculate the mass as:
mass = volume*density

= 46.1 g
From given info, potassium bromide solution is 8.34% potassium bromide by mass. It means if we have 100 grams of the solution then 8.34 grams of potassium bromide is present in. We need to calculate how many grams of potassium bromide are present in 46.1 grams of the solution.
The calculations could easily be done using dimensional analysis as:

= 3.84 g KBr
Hence, 3.84 grams of KBr are present in 44.8 mL of the solution.
A. helium, neon and argon, because they are in the same group or column
The letter Ne with eight dots. Because it is a Noble Gas, it has eight valence electrons.
Answer:
1244 students
Explanation:
That would be y = 82*3 + 998
= 1244.