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jeyben [28]
2 years ago
13

A balloon is inflated to a volume of 7.0 L 7.0 L on a day when the atmospheric pressure is 765 mmHg. The next day, as a storm fr

ont arrives, the atmospheric pressure drops to 737 mmHg 737 mmHg . Assuming the temperature remains constant, what is the new volume of the balloon, in liters?
Chemistry
1 answer:
kirill115 [55]2 years ago
6 0

Answer:

The new volume is 7.27 L

Explanation:

Step 1: Data given

The initial volume of the balloon = 7.0 L

The pressure = 765 mmHg = 765/760 atm = 1.00658 atm

The pressure drops to 737 mmHg = 737/ 760 atm = 0.969737

The temperature remains constant

Step 2: Calculate the new volume

P1*V1 = P2*V2

⇒with P1 = the initial pressure in the balloon = 765 mmHg

⇒with V1 = the initial volume = 7.0L

⇒with P2 = the decreased pressure = 737 mmHg

⇒with V2 = the new volume = TO BE DETERMINED

765 mmHg * 7.0 L = 737 mmHG * V2

V2 = (765 mmHG * 7.0 L) / 737 mmHG

V2 = 7.27 L

The new volume is 7.27 L

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Remember:
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3 0
2 years ago
Suppose a solution is prepared by dissolving 15.0 g NaOH in 0.150 L of 0.250 M nitric acid. What is the final concentration of O
Kipish [7]

Answer:

2.25 M is the final concentration of hydroxide ions ions in the solution after the reaction has gone to completion.

Explanation:

Moles of NaOH = \frac{15.0 g}{40 g/mol}=0.375 mol

Molarity of the nitric acid solution = 0.250 M

Volume of the nitric solution = 0.150 L

Moles of nitric acid = n

Molarity=\frac{Moles}{Volume(L)}

n=0.250 M\times 0.150 L=0.0375 mol

NaOH+HNO_3\rightarrow NaNO_3+H_2O

According to reaction, 1 mole of nitric acid recats with 1 mole of NaOH, then 0.0375 moles of nitric acid will react with :

\frac{1}{1}\times 0.0375 mol of NaOH

Moles of NaOH left unreacted  in the solution =

= 0.375 mol - 0.0375 mol = 0.3375 mol

NaOH(aq)\rightarrow Na^+(aq)+OH^-(aq)

1 mole of sodium hydroxide gives 1 mol of sodium ions and 1 mole of hydroxide ions.

Then 0.3375 moles of NaOH will give :

1\times 0.3375 moles=0.3375 mol of hydroxide ion

The molarity of hydroxide ion in solution ;

=\frac{0.3375 mol}{0.150 L}=2.25 M

2.25 M is the final concentration of hydroxide ions ions in the solution after the reaction has gone to completion.

3 0
3 years ago
How many watts of power (W) do you expend when you exert a force of 10 N that moves a
mihalych1998 [28]

Answer:

Power = 7.5 watt

Explanation:

Given data:

Power expend = ?

Force applied = 10 N

Distance cover = 1.5 m

Time = 2 s

Solution:

Power = work/ time

First of all we will calculate work.

Work = Force × distance

Work = 10 N × 1.5 m

Work = 15 N.m

Now we will calculate the power.

Power = 15 N.m / 2s

N.m/s = 1 watt

Power = 7.5 watt

7 0
3 years ago
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WARRIOR [948]

Answer:

                                 Sedimentary rock

Metamorphic rock                                 Igneous rock

4 0
2 years ago
On the pH scale pure water has a pH of<br> A. 0<br> B. 7<br> C. 14
konstantin123 [22]

Answer:its b 7

Explanation:

7 is neutral and pure water is the middle man

7 0
3 years ago
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