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BigorU [14]
3 years ago
13

An empty 10-ml volumetric flask weighs 10.267 g. after filling to the mark with distilled water at 20°c, the mass is 20.219 g. w

hat is the mass of water in the flask
Chemistry
1 answer:
Dahasolnce [82]3 years ago
3 0
Ok, so... 20.219 grams is the mass of the flask with the water in it.
10.267 grams is the mass of only the flask. Subtract them to find the water mass.

20.219 g (flask+water) - 10.267 g (flask) = 9.952 g (water)
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What is the atomic mass of<br> an atom?
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Answer:

1 unit

Explanation:

It is expressed as a multiple of one-twelfth the mass of the carbon-12 atom, 1.992646547 × 10−23 gram, which is assigned an atomic mass of 12 units.

1/12 * 12 = 1. I think so.

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Imagine that you traveled to the Moon for a vacation and discovered that your weight is different there. How would your weight b
dmitriy555 [2]

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8 0
2 years ago
The variable that a scientist observes to change while conducting an experiment is called the ___ variable.
Nimfa-mama [501]

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4 0
3 years ago
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Which reaction has the highest atom economy for the production of C02?​
In-s [12.5K]

The highest atom economy

2CO + O₂ ⇒ 2CO₂

<h3>Further explanation</h3>

Given

The reaction for the production of CO₂

Required

The highest atom economy

Solution

In reactions, there are sometimes unwanted products that can be said to be a by-product or a waste product. Meanwhile, the desired product can be said to be a useful product, which can be shown as the atom economy

of the reaction

the higher the atomic economy value of a reaction, the smaller the waste/ byproducts produced, so that less energy is wasted

The general formula:

Atom economy = (mass of useful product : mass of all reactants/products) x 100

<em>or </em>

Atom economy = (total formula masses of useful product : total formula masses of all reactants/products) x 100

So a reaction that only produces one product will have the highest atomic value, namely the reaction in option C

4 0
2 years ago
Problem Page Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 5.2 g o
stich3 [128]

Answer: 0.0 grams

Explanation:

To calculate the moles, we use the equation:

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a) moles of butane

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b) moles of oxygen

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According to stoichiometry :

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Thus 0.09 moles of butane will require =\frac{13}{2}\times 0.09=0.585moles  of O_2

Butane is the limiting reagent as it limits the formation of product and oxygen is present in excess as (1.02-0.585)=0.435 moles will be left.

Thus all the butane will be consumed and 0.0 grams of butane will be left.

7 0
2 years ago
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