1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
BigorU [14]
3 years ago
13

An empty 10-ml volumetric flask weighs 10.267 g. after filling to the mark with distilled water at 20°c, the mass is 20.219 g. w

hat is the mass of water in the flask
Chemistry
1 answer:
Dahasolnce [82]3 years ago
3 0
Ok, so... 20.219 grams is the mass of the flask with the water in it.
10.267 grams is the mass of only the flask. Subtract them to find the water mass.

20.219 g (flask+water) - 10.267 g (flask) = 9.952 g (water)
You might be interested in
Tamoxifen is a drug used to prevent recurrence of certain types of breast cancers that require estrogen to grow. Tamoxifen binds
fredd [130]

Answer:

Tamoxifen is an irreversible, competitive inhibitor.

Explanation:

In order to binds to the active site of the estrogen receptor protein, tamoxifen have to compete with the other chemical compound, and inhibits the estrogen release, so it is a competitive inhibitor. Then, you said that when tamoxifen binds to the receptor,  the protein is permanently deactivated, so it is also irreversible.

8 0
3 years ago
In the Minnesota Department of Health set a health risk limit for acetone in groundwater of 60.0 μg/L . Suppose an analytical ch
siniylev [52]

Answer:

m = 4.7 μg

Explanation:

Given data:

density of acetone = 60.0  μg/L

Volume = 79.0 mL

Mass = ?

Solution:

Formula:

d = m/v

v = 79.0 mL × 1L /1000 mL

v = 0.079 L

Now we will put the values on formula:

d = m/v

60.0  μg/L = m/0.079 L

m = 60.0 μg/L × 0.079 L

m = 4.7 μg

So health risk limit for acetone = 4.7  μg

3 0
3 years ago
How many moles of atoms are in 5.00 g of 13C
Illusion [34]
  <span>Mr = 13 g / mol 
mass = 5 g 
Mol = 5/13 mol :)</span>
7 0
3 years ago
in a typical person, the level of glucose is about 85 mg/ 100 mL of blood. if an average body contains about 11 pt of blood, how
Vanyuwa [196]

Let's note that 1 pint = 473.1765 mL, so 11 pints should be 5204.9415 mL.

We make a proportion out of the word problem

(85 mg glucose/ 100 mL) times (1 g/ 1000 mg) = 4.4242 grams of glucose

5 0
3 years ago
Using standard reduction potentials from the ALEKS Data tab, calculate the standard reaction free energy for the following redox
stealth61 [152]

Answer:

-973 KJ

Explanation:

The balanced reaction equation is;

N2H4(aq) + 2Cl2(g) + 4OH^-(aq)---------> 4Cl-(aq) + 4H ^+(aq) + 4OH^-(aq) + N2(g)

Reduction potential of hydrazine = -1.16 V

Reduction potential of chlorine = 1.36 V

From;

E°cell= E°cathode - E°anode

E°cell= 1.36 - (-1.16)

E°cell= 2.52 V

∆G°=- nFE°cell

n= number of moles of electrons = 4

F= Faraday's constant = 96500 C

E°cell = 2.52 V

∆G°=- (4 × 96500 × 2.52)

∆G°= -972720 J

∆G°= -972.72 KJ

7 0
3 years ago
Other questions:
  • Calculate the value of D at 575°C for the diffusion of some species in a metal for which the values of D0 and Qd are 4.5 × 10-5
    14·1 answer
  • Consider the combustion of octane (C8H18), a primary component of gasoline.
    8·1 answer
  • How much energy in kilojoules is released when 23.4 g of ethanol vapor at 83.0 ∘C is cooled to -15.0 ∘C ?
    7·1 answer
  • PLEASE HELP ME ASAP PLEASE!!!
    15·1 answer
  • A 0.1018 g sample of organic compound with a molar mass of 225.4 g/mol was
    5·1 answer
  • Heptane and water do not mix, and heptane has a lower density (0.684 g/mL.) than water (1.00 g/
    6·1 answer
  • PERIODIC TABLE TEST WILL GIVE BRAINLIEST!
    13·2 answers
  • Vinegar, which contains acetic acid, is used in foods and has few safety concerns​. Hydrochloric acid is used in chemistry labs
    15·1 answer
  • Where do you find the protons and neutrons of an atom?
    12·1 answer
  • How many litres of hydrogen is present in 12 grams of hydrogen​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!