The point (2,0) represents a relative minimum and an x-intercept.
<h3>How to determine the property?</h3>
The missing graphed function is added as an attachment
The point (2,0) means that:
x = 2 and y = 0
On the attached graph, we can see that the graph touches the x-axis at (2,0); this represents the x-intercept
Also, the graph has a minimum at (2,0); this represents the relative minimum
Hence, the point (2,0) represents a relative minimum and an x-intercept.
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Answer:
f^-1(x) = (x -2)/3
Step-by-step explanation:
To find the inverse function, swap x and y, then solve for y.
y = 3x +2 . . . . given function
x = 3y +2 . . . . inverse relation
x -2 = 3y . . . . subtract 2
(x -2)/3 = y . . . divide by 3
f^-1(x) = (x -2)/3 . . . . in functional form
Answer:
Draw a line AB
Take a point C on AB
Fix the tip of compass at C and with a fix radius, cut AB on both sides of C
Mark those points D and E
Fix the tip of compass on D, and with the same radius, draw an arc above C
Do the same with E
Those two arcs will intersect at a point, mark the point F
Make a line passing through both C and F
Line CF is perpendicular to AB
Yes, with exceptions. It is possible to express every decimal as a fraction,
without rounding, unless the decimal is non-terminating AND non-repeating.
When we Simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3], the result obtained is (1/18)x^2
<h3>Data obtained from the question</h3>
- [(x^2)^3 × 5x] / [6x^2 × 15x^3]
- Simplification =?
<h3>How to simplify [(x^2)^3 × 5x] / [6x^2 × 15x^3]</h3>
[(x^2)^3 × 5x] / [6x^2 × 15x^3]
Recall
(M^a)^b = M^ab
Thus,
(x^2)^3 = x^6
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = [x^6 × 5x] / [6x^2 × 15x^3]
Recall
M^a × M^b = M^(a+b)
Thus,
x^6 × 5x = 5x^(6 + 1) = 5x^7
6x^2 × 15x^3] = (6×15)x^(2 + 3) = 90x^5
- [x^6 × 5x] / [6x^2 × 15x^3] = 5x^7 / 90x^5
Recall
M^a ÷ M^b = M^(a - b)
Thus,
5x^7 ÷ 90x^5 = (5÷90)x^(7 - 5) = (1/18)x^2
Therefore,
- [(x^2)^3 × 5x] / [6x^2 × 15x^3] = (1/18)x^2
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