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Angelina_Jolie [31]
3 years ago
5

What quantity of heat is required to raise the temperature of 460g of aluminum from 15C to 85C?

Chemistry
1 answer:
Hoochie [10]3 years ago
6 0

Answer:

Q = 28.9 kJ

Explanation:

Given that,

Mass of Aluminium, m = 460 g

Initial temperature, T_i=15^{\circ} C

Final temperature, T_f=85^{\circ}

We know that the specific heat of Aluminium is 0.9 J/g°C. The heat required to raise the temperature is given by :

Q=mc\Delta T\\\\Q=mc(T_f-T_i)\\\\Q=460\ g\times 0.9\ J/g^{\circ} C\times (85-15)^{\circ} C\\\\Q=28980\ J\\\\\text{or}\\\\Q=28.9\ kJ

So, 28.9 kJ of heat is required to raise the temperature.

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three of the following are base units used in the metric system. which is not a base unit? meter liter kilogram gram
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The base units used in the metric system are meter for the measurement of distance or displacement, liter as unit measurement of volume, kilogram as a unit of measurement of mass and seconds as unit of measurement of time. The answer is here is D. gram.
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A compound of uranium and fluorine is used to generate uranium for nuclear power plants. The gas can be decomposed to yield 2.09
Artemon [7]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

The gas can be decomposed to yield 2.09 parts by mass of uranium for every 1 part by mass of fluorine.If the relative mass of a uranium atom is 238 and the relative mass of a fluorine atom is 19, <span> the number of fluorine atoms that are combined with one uranium atom. is 6</span>

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3 years ago
Transport of aspirin is expected to be faster in the ____. The speed of nonmediated absorption depends strongly on the polarity
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Answer:

Idk

Explanation:

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7 0
3 years ago
Heat of fusion (?Hfus) is used for calculations involving a phase change between solid and liquid, with no temperature change. F
Butoxors [25]

Answer:

q = 38,5 kJ

Explanation:

In its melting point, at 0°C, water is liquid. The boiling point of water is 100°C. It is possible to estimate the heat you required to raise the temperature of water from 0°C to 100°C using:

q = C×m×ΔT

Where C is specific heat of water (4,184J/g°C), m is mass of water (92,0g) and ΔT is change in temperature (100°C-0°C = 100°C)

Replacing:

q = 4,184J/g°C×92,0g×100°C

q = 38493 J, in kilojoules:

<em>q = 38,5 kJ</em>

<em></em>

I hope it helps!

6 0
3 years ago
Propane reacts with 3.15moles of oxygen how much propane reacts with oxygen​
Inessa [10]

27.7g

Explanation:

Given parameters:

Number of moles of oxygen = 3.15moles

Unknown:

Mass of reacting propane = ?

Solution:

   Equation of the reaction:

                   C₃H₈ + 5O₂   →    3CO₂    +     4H₂O

 We work from the known to the unknown parameters.

The known in this expression is the number of moles of oxygen.

   In the reaction:

                   5 moles of oxygen gas reacts with 1 mole of propane

  3.15 mole of oxgen gas will react with    \frac{3.15}{5} = 0.63moles

Number of moles of reacting propane gas is 0.63moles

To find the mass;

         mass = number of moles x molar mass = 0.63 x molar mass

molar mass of propane = (3 x 12) + (8x1) = 44g/mol

         mass of propane = 0.63 x 44 = 27.7g

Learn more:

Combustion reaction brainly.com/question/6126420

#learnwithBrainly

8 0
3 years ago
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