1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
diamong [38]
3 years ago
14

What is the mass in grams of 2.30 x10^23 molecules of Fluorine

Chemistry
1 answer:
Jobisdone [24]3 years ago
8 0

Answer:

14.512g

Explanation:

Using the expression

mole = Number of molecules/6.022 x 10^23

mole of Fluorine = 2.30 x10^23/6.022 x 10^23

                             =  0.3819 mol

However,

mole = mass / molarmass

Mass of Fluorine = mole of Fluorine/ Molarmass of Fluorine

Molarmass of Fluorine = 18.998 x 2 = 37.996 g/mol

Mass of Fluorine = 0.3819mol/37.996g/mol

                              = 14.512g

You might be interested in
As with any drug, aspirin (acetylsalicylic acid) must remain in the bloodstream long enough to be effective. Assume that the rem
Olenka [21]

Answer:

180 mg

Explanation:

For a first-order reaction, we can calculate the amount of aspirine (A) at a certain time (t) using the following expression.

A=A_{0}.e^{-k.t}

where,

k: rate constant

A₀: initial amount

If we know the half-life (t_{1/2}) we can calculate the rate constant.

k=\frac{ln2}{t_{1/2}} =\frac{ln2}{3h} =0.2h^{-1}

When t = 4 h and A₀ = 400 mg, A is:

A=400mg.e^{-0.2h^{-1}\times 4h} =180mg

4 0
3 years ago
Helppppppppppppppppppppp
alukav5142 [94]

decameters - meters: multiply by 10

meters to meters: multiply by 1

centimeters to meters: divide by 100

millimeters to meters: divide by 1000

For the rows at the bottom:

hectometer row: 100, multiply by 100, 4500

decameter row: 10, multiply by 10, 450

meter row: 1, multiply by 1, 45

decimeter row: 0.1, divide by 10, 4.5

centimeter row: 0.01, divide by 100, 0.45

im guessing theres a millimeter row at the bottom:

millimeter row: 0.001, divide by 1000, 0.045


hope this helps!

5 0
3 years ago
what would the percentage of thorium-232 ( parent compound) be in a rock that was dated at 1.8 billion years
vovikov84 [41]

The half-life of Th-232 is 1.405 × 10¹⁰ years  

Time elapsed = 2.8 x 10⁹ years  

Equation of radioactive decay:

A = A₀ = (1/2)^ t/t₁/₂

Thus, the percentage of thorium-232 in the rock that was dated at 2.8 billions year = 87.1%

7 0
3 years ago
Cho 2.3 gam natri vào 100ml nước . Tính nồng độ dung dịch thu được ( C% )
Anton [14]

Answer:

maybe speak in english than we can understand and help you sorryy

8 0
2 years ago
Sodium tripolyphosphate is used in detergents to make them effective in hard water. Calculate the oxidation number of phosphorus
xz_007 [3.2K]
The answer for this question is A
4 0
3 years ago
Read 2 more answers
Other questions:
  • Match the correct properties and characteristics of each type of rock?
    11·2 answers
  • Suppose that 0.88g of water condenses on a 75.0-g block of iron that is initially at 22 degrees Celsius. If the heat released du
    11·1 answer
  • PLEASE HELP 15 PTS!!!!! How can chemistry be used to improve energy efficiency?
    9·1 answer
  • How many moles of air must escape from a 10-m  8.0-m  5.0-m room when the temperature is raised from 0c to 20c? assume the p
    10·1 answer
  • What is the frequency of a photon with a wavelength of 1040 nm. Report your answers to three significant digits. The frequency i
    12·1 answer
  • A sample of mercury has a mass of 607.0 lb and a volume of 0.717 ft. What is its specific gravity? Number SG= What are the units
    7·1 answer
  • Scientists are studying different jackets made for extremely cold, snowy weather. They are trying to find jackets
    13·1 answer
  • Burning fossil fuels causes atmospheric pollution write one effect for each pollutant in table 2.
    15·1 answer
  • For the following equation to be bal
    15·1 answer
  • Three examples where is helpful to have a low reaction rate
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!