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coldgirl [10]
3 years ago
9

17. An industrially important element contains

Chemistry
1 answer:
likoan [24]3 years ago
8 0

Answer:

Iron (Fe)

Explanation:

The number of electrons (-) is usually the same as the number of protons (+) in the atom of the element (unless it is an ion).

The element described has 26 electrons, so we can assume that it has 26 protons as well. The number of protons in an atom is the atomic number of element that the atom is.

Element 26 on the PTE is Iron (Fe), which does rust (oxidation) in air and water.

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Select the word or phrase from the drop-down menu to describe ionic compounds. A formula unit represents the simplest ratio of e
Gelneren [198K]

Answer:

CRYSTAL

MANY ATOMS THAT ARE ARRANGE IN A REGULAR PATTERN

1:1

Explanation:

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What is the transition element which despite its strength (rigidity), it is characterized by being ductile, and by its high resi
uranmaximum [27]

Titanium is ductile and has high resistance for heat despite its strength.

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  • known as the strongest metal with high rigidity
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  • low density
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5 0
3 years ago
A form of energy that is related to its temperature...
Montano1993 [528]

Answer:

thermal

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4 0
2 years ago
What is the final temperature of the solution formed when 1.52 g of NaOH is added to 35.5 g of water at 20.1 °C in a calorimeter
Inessa [10]

Answer : The final temperature of the solution in the calorimeter is, 31.0^oC

Explanation :

First we have to calculate the heat produced.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy change = -44.5 kJ/mol

q = heat released = ?

m = mass of NaOH = 1.52 g

Molar mass of NaOH = 40 g/mol

\text{Moles of }NaOH=\frac{\text{Mass of }NaOH}{\text{Molar mass of }NaOH}=\frac{1.52g}{40g/mole}=0.038mole

Now put all the given values in the above formula, we get:

44.5kJ/mol=\frac{q}{0.038mol}

q=1.691kJ

Now we have to calculate the final temperature of solution in the calorimeter.

q=m\times c\times (T_2-T_1)

where,

q = heat produced = 1.691 kJ = 1691 J

m = mass of solution = 1.52 + 35.5 = 37.02 g

c = specific heat capacity of water = 4.18J/g^oC

T_1 = initial temperature = 20.1^oC

T_2 = final temperature = ?

Now put all the given values in the above formula, we get:

1691J=37.02g\times 4.18J/g^oC\times (T_2-20.1)

T_2=31.0^oC

Thus, the final temperature of the solution in the calorimeter is, 31.0^oC

4 0
3 years ago
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