If Ka for HCN is 6. 2×10^−10 at 25 °C, then the value of Kb for cn− at 25 °C is 1.6 × 10^(-5).
<h3>What is base dissociation constant? </h3><h3 />
The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.
The dissociation reaction of hydrogen cyanide can be given as
HCN --- (H+) + (CN-)
Given,
The value of Ka for HCN is 6.2× 10^(-10)
The correlation between base dissociation constant and acid dissociation constant is
Kw = Ka × Kb
Kw = 10^(-14)
Substituting values of Ka and Kw,
Kb = 10^(-14) /{6.2×10^(-10) }
= 1.6× 10^(-5)
Thus, the value of base dissociation constant at 25°C is 1.6 × 10^(-5).
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When water chemically combines with carbon dioxide, a Carbonic acid is formed.
<u>Explanation</u>:
- Carbon dioxide responds with water in a solution to form a weak acid, carbonic acid. Carbonic acid disassociates into hydrogen particles and bicarbonate particles. The hydrogen particles and water respond with the most basic minerals modifying the minerals.
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Carbon dioxide and the other atmospheric gases disintegrate in surface waters. Dissolved gases are in equilibrium with the gas in the atmosphere. Carbon dioxide responds with water in a solution to form the weak acid, carbonic acid. Carbonic acid disassociates into hydrogen particles and bicarbonate particles.
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The hydrogen particles and water respond with the most basic minerals altering the minerals. The results of enduring are prevalently clays and soluble particles, for example, calcium, iron, sodium, and potassium. Bicarbonate particles additionally remain in solution; a remnant of the carbonic acid that was utilized to weather the rocks.
Answer:
β-hydroxyaldehyde (an aldol) namely 3-Hydroxy butanal.
Explanation:
When acetaldehyde is treated with dil.NaOH it undergoes self condensation as it contains alpha-hydrogen atom in its compound forming β-hydroxyaldehyde (an aldol) namely 3-Hydroxy butanal. This compound upon further heating will eliminate a molecule of water forming aldol condensation product namely Crotonaldehyde Or But-2-en-al. see the diagram attached.
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It will have traveled 0.78 m. You find this by multiplying .013 by 60
