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3 years ago

Why is it necessary for the triceps to be the contracting muscle when throwing

Chemistry

1 answer:

Morgarella [4.7K]3 years ago

3 0

Explanation:

The triceps contract to allows the arm to extend and flex while throwing

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Sulfur trioxide is a gas that reacts with liquid water to produce aqueous sulfuric Acid or acid rain what is the equation for th

bearhunter [10]

Answer:

SO₃(g) + H₂O(l) → H₂SO₄(aq)

Explanation:

The<em> molecular formula for the involved species</em> are:

Sulfur trioxide = SO₃. ("trioxide" indicates the presence of 3 oxygen atoms).

Water = H₂O

Sulfuric acid = H₂SO₄

With the above information in mind we can proceed to write the reaction equation:

SO₃(g) + H₂O(l) → H₂SO₄(aq)

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3 years ago

Someone pls help with this

Anettt [7]

Question 3 is uniformitarianism
Question 4 is sedimentary rock

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3 years ago

How many nitrogen atoms are in 4AgNO3

tensa zangetsu [6.8K]

Answer:

Silver/AG= 4

Nitrogen/N=4

Oxygen/O=12

Explanation:

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3 years ago

Definition of diameter?

astra-53 [7]

Answer:

a straight line passing from side to side through the center of a body or figure, especially a circle or sphere.

Explanation:

a straight line passing from side to side through the center of a body or figure, especially a circle or sphere.

3 0

3 years ago

I2(g) + Cl2(g)2ICl(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.62 mol

galina1969 [7]

Answer:

The change in entropy of the surrounding is -146.11 J/K.

Explanation:

Enthalpy of formation of iodine gas = $\Delta H_f_{(I_2)}=62.438 kJ/mol$

Enthalpy of formation of chlorine gas = $\Delta H_f_{(Cl_2)}=0 kJ/mol$

Enthalpy of formation of ICl gas = $\Delta H_f_{(ICl)}=17.78 kJ/mol$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]$

For the given chemical reaction:

$I_2(g)+Cl_2(g)\rightarrow 2ICl(g),\Delta H_{rxn}=?$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(2\times \Delta H_f_{(ICl)})]-[(1\times \Delta H_f_{(I_2)})+(1\times \Delta H_f_{(Cl_2)})]$

$=[2\times 17.78 kJ/mol]-[1\times 0 kJ/mol+1\times 62.436 kJ/mol]=-26.878 kJ/mol$

Enthaply change when 1.62 moles of iodine gas recast:

$\Delta H= \Delta H_{rxn}\times 1.62 mol=(-26.878 kJ/mol)\times 1.62 mol=-43.542 kJ$

Entropy of the surrounding = $\Delta S^o_{surr}=\frac{\Delta H}{T}$

$=\frac{-43.542 kJ}{298 K}=\frac{-43,542 J}{298 K}=-146.11 J/K$

1 kJ = 1000 J

The change in entropy of the surrounding is -146.11 J/K.

4 0

3 years ago